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joja [24]
2 years ago
10

What property describes the number sentence 6+0=6

Mathematics
1 answer:
kobusy [5.1K]2 years ago
7 0
Additive Identity Property is the answer.

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Evaluate the expression for x=6<br> 4×+6
alexira [117]

Answer:

30

Step-by-step explanation:

x=6

4 by 6 =24

24 + 6 =30

7 0
3 years ago
Jenny’s mom is 36 years old. If Jenny’s great grandmother is 90 years old, what percent of Jenny’s mother’s age is Jenny’s great
Effectus [21]

Answer:

13.1

Step-by-step explanation:

12/90=x/100%

cross multiply

1200%=90x

13 1/3%=x

8 0
3 years ago
Helpp me will give brainliest!!!!
olga_2 [115]

Let's find area of the base.: 5x4.3=21.5, 21.5/2=10.75

Area of the Faces : 5x3=15/2=7.5x4=30

Let's add 10.75 +30=40.75

5 0
2 years ago
Use fundamental theorem of calculus to find derivative of the function LOOK AT PHOTO
kykrilka [37]

Let c > 0. Then split the integral at t = c to write

f(x) = \displaystyle \int_{\ln(x)}^{\frac1x} (t + \sin(t)) \, dt = \int_c^{\frac1x} (t + \sin(t)) \, dt - \int_c^{\ln(x)} (t + \sin(t)) \, dt

By the FTC, the derivative is

\displaystyle \frac{df}{dx} = \left(\frac1x + \sin\left(\frac1x\right)\right) \frac{d}{dx}\left[\frac1x\right] - (\ln(x) + \sin(\ln(x))) \frac{d}{dx}\left[\ln(x)\right] \\\\ = -\frac1{x^2} \left(\frac1x + \sin\left(\frac1x\right)\right) - \frac1x (\ln(x) + \sin(\ln(x))) \\\\ = -\frac1{x^3} - \frac{\sin\left(\frac1x\right)}{x^2} - \frac{\ln(x)}x - \frac{\sin(\ln(x))}x \\\\ = -\frac{1 + x\sin\left(\frac1x\right) + x^2\ln(x) + x^2 \sin(\ln(x))}{x^3}

8 0
2 years ago
Adult female height is normally distributed with a mean of 65.3 inches and a standard deviation of 2.32 inches. a) If an adult f
emmasim [6.3K]

Answer:

0.0423 is the probability that the adult female has a height less than 61.3 inches.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 65.3 inches

Standard Deviation, σ = 2.32 inches

We are given that the distribution of adult female height is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(adult female has a height less than 61.3 inches)

P( x < 61.3) = P( z < \displaystyle\frac{61.3 - 65.3}{2.32}) = P(z < -1.7241)

Calculation the value from standard normal z table, we have,  

P(x < 61.3) =0.0423 = 4.23\%

0.0423 is the probability that the adult female has a height less than 61.3 inches.

5 0
3 years ago
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