ACD by AAS.
We're given m1 = m2, ADC = ADB, and both triangles share AD, so it must be AAS.
ABD by SAS.
We're given AB = AE and AC = AD, but the middle part is a mystery. We're not given BD and CE/ADB and ACE so it's pretty hard to know. Could be SAS or SSS. If you have either BD and CE, it's SSS. If you have ADB and ACE, it's SAS.
Took Geometry 4 years ago so I'm a bit iffy on the second. Forgive me D:
I think the answer is B because Annuity is a fixed sum of money paid each year
First find the gradient of line AB
14--3/7--10
17/17 = 1
As CD is perpendicular to AB take the negative reciprocal of the gradient to AB to find gradient of CD
Gradient of CD = -1
to find y intercept use points given
12=(-1 x 5) +c
17 = c
C is the y intercept so for question 1 the answer is 3
for the second question just plug values into the equation and see if you get the right y value
Here the only number that works is -2
for question 2
the answer is 2
Answer:
Step-by-step explanation:
Hello!
X₁: speed of a motorcycle at a certain intersection.
n₁= 135
X[bar]₁= 33.99 km/h
S₁= 4.02 km/h
X₂: speed of a car at a certain intersection.
n₂= 42 cars
X[bar]₂= 26.56 km/h
S₂= 2.45 km/h
Assuming
X₁~N(μ₁; σ₁²)
X₂~N(μ₂; σ₂²)
and σ₁² = σ₂²
<em>A 90% confidence interval for the difference between the mean speeds, in kilometers per hour, of motorcycles and cars at this intersection is ________.</em>
The parameter of interest is μ₁-μ₂
(X[bar]₁-X[bar]₂)± *
[(33.99-26.56) ± 1.654 *()]
[6.345; 8.514]= [6.35; 8.51]km/h
<em>Construct the 98% confidence interval for the difference μ₁-μ₂ when X[bar]₁= 475.12, S₁= 43.48, X[bar]₂= 321.34, S₂= 21.60, n₁= 12, n₂= 15</em>
[(475.12-321.34) ± 2.485 *()]
[121.96; 185.60]
I hope this helps!