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Lynna [10]
3 years ago
9

-PLEASE HELP ASAP-

Mathematics
1 answer:
jenyasd209 [6]3 years ago
5 0
The answer to the first equation is A.
the second equation is B
the third eqation is C
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HOW TO FINISH IT? Complete the table and pattern. Determine the common difference. Write the explicit rule.
sp2606 [1]

a_{n} = a_{1} + d(n - 1)   <em> a₁ is the first term, d is the difference, and n is the term</em>

a₁ = -5

d = -5

a_{n} = -5 - 5(n - 1)

a_{n} = -5 - 5n + 5  

a_{n} = -5n            <em>explicit formula</em>

a_{n} = -5a_{n-1}       <em>recursive formula</em>

4 0
3 years ago
Help plz <br> correct answer get brainliest
Elina [12.6K]
No it is a straight line they are not collinear
6 0
4 years ago
Last weekend, Carlos rode his bicycle for 3 hours and traveled 27 miles. On average, at what rate did Carlos travel on his bicyc
mash [69]
Carlos rode an average of 9 miles every hour on his bicycle. It is because 3*9=27 and the distance is rate multiplied by time. use the formula and check it!

Hope I helped.

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5 0
3 years ago
Ace Landscape buys 100 shovels for $15 each. Ace sells all 100 shovels at $29.99. What is his profit?
Yanka [14]
$29.99=$30
$30-$15=$15 
Ace's profit is $15
7 0
3 years ago
the mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.5 %. assume
zhuklara [117]
Given:
Population proportion, \mu _{p} = 57% = 0.57
Population standard deviation, σ  = 3.5% = 0.035
Sample size, n = 40
Confidence level = 95%

The standard error is
SE_{p} =  \sqrt{ \frac{p(1-p)}{n} } = \sqrt{ \frac{0.57*0.43}{40} } =0.0783

The confidence interval is 
\hat{p} \pm z^{*}SE_{p}
where
\hat{p} = sample proportion
z* = 1.96 at the 95% confidence lvvel

The sample proportion lies in the interval
(0.57-1.96*0.0783, 0.57+1.96*0.0783) = (0.4165, 0.7235)

Answer: Between 0.417 and 72.4), or between (41% and 72%)

8 0
4 years ago
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