Answer:
83°C
Explanation:
The following were obtained from the question:
M = 40g
C = 4.2J/g°C
T1 = 91°C
T2 =?
Q = 1300J
Q = MCΔT
ΔT = Q/CM
ΔT = 1300/(4.2x40)
ΔT = 8°C
But ΔT = T1 — T2 (since the reaction involves cooling)
ΔT = T1 — T2
8 = 91 — T2
Collect like terms
8 — 91 = —T2
— 83 = —T2
Multiply through by —1
T2 = 83°C
The final temperature is 83°C
Answer:
A. c. Keq=[H2]^2[S2]/[H2S]^2
B. b. Keq=[COCl2]/[CO][Cl2]
Explanation:
Hello,
In this case, considering the law of mass action which states that the equilibrium expression is written in terms of the concentration of products divided by the concentration of reactants considering the stoichiometric coefficients as powers we obtain:
A. For the reaction:
The equilibrium expression is:
![Keq=\frac{[H_2]^2[S_2]}{[H_2S]^2}](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BH_2%5D%5E2%5BS_2%5D%7D%7B%5BH_2S%5D%5E2%7D)
Therefore, answer is c. Keq=[H2]^2[S2]/[H2S]^2.
B. For the reaction:
The equilibrium expression is:
![Keq=\frac{[COCl_2]}{[CO][Cl_2]}](https://tex.z-dn.net/?f=Keq%3D%5Cfrac%7B%5BCOCl_2%5D%7D%7B%5BCO%5D%5BCl_2%5D%7D)
Therefore, answer is b. Keq=[COCl2]/[CO][Cl2].
Regards.
<span>Density = mass / volume
3.32 kg = 3320 g
volume mass / density
3320 / 1.11 = 2990.99</span>
Answer:
well what above wave?? do you have a picture
Explanation:
Answer:
F = 30 N
Explanation:
Given data:
Mass of toy train = 1.5 kg
Acceleration of train = 20 m/s²
Amount of force acting on it = ?
Solution:
The net force on object is equal to the its mass multiply by its acceleration.
Formula:
F = ma
F = force
m = mass
a = acceleration
Now we will put the values in formula.
F = 1.5 kg × 20ms⁻²
F = 30 kg.ms⁻²
kg.ms⁻² = N
F = 30 N
