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2 years ago

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Chemistry

1 answer:

DerKrebs [107]2 years ago

7 0

Answer:

F = 30 N

Explanation:

Given data:

Mass of toy train = 1.5 kg

Acceleration of train = 20 m/s²

Amount of force acting on it = ?

Solution:

The net force on object is equal to the its mass multiply by its acceleration.

Formula:

F = ma

F = force

m = mass

a = acceleration

Now we will put the values in formula.

F = 1.5 kg × 20ms⁻²

F = 30 kg.ms⁻²

kg.ms⁻² = N

F = 30 N

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If you have 40.0 g HCl and 40.0 g NaHCO3, do you have the same number of moles of each?

umka2103 [35]

They both have a different number of moles

<h3>Further explanation</h3>

Given

40 g HCl

40 g NaHCO3

Required

moles

Solution

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

n = mass : molar mass

So the moles of a compound are affected by its molar mass (inversely proportional)

The larger the molar mass (of the same mass), the smaller the moles

molar mass HCl = 58.5 g/mol

molar mass NaHCO3 = 84 g/mol

mol HCl :

= 40 : 58.5

= 0.684

mol NaHCO# :

= 40 : 84

= 0.476

3 0

3 years ago

A 2.832 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 6.439 grams of CO2 and 2

strojnjashka [21]

Answer: The empirical and molecular formula for the given organic compound is $C_2H_2O_4$ and $C_6H_{12}O_2$ respectively.

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=6.439g$

Mass of $H_2O=2.636g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 6.439 g of carbon dioxide, $\frac{12}{44}\times 6.439=1.756g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 2.636 g of water, $\frac{2}{18}\times 2.636=0.293g$ of hydrogen will be contained.

Mass of oxygen in the compound = (2.832) - (1.756 + 0.293) = 0.783 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{1.756g}{12g/mole}=0.146moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.293g}{1g/mole}=0.293moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.783g}{16g/mole}=0.049moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.049 moles.

For Carbon = $\frac{0.146}{0.049}=2.97\approx 3$

For Hydrogen = $\frac{0.293}{0.049}=5.97\approx 6$

For Oxygen = $\frac{0.049}{0.049}=1$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 3 : 6 : 1

Hence, the empirical formula for the given compound is $C_3H_{6}O_1=C_3H_6O$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

We are given:

Mass of molecular formula = 116.2 g/mol

Mass of empirical formula = 58 g/mol

Putting values in above equation, we get:

$n=\frac{116.2g/mol}{58g/mol}=2$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(3\times 2)}H_{(6\times 2)}O_{(1\times 2)}=C_6H_{12}O_2$

Thus, the empirical and molecular formula for the given organic compound is $C_3H_6O$ and $C_6H_{12}O_2$ respectively.

7 0

3 years ago

In a calorimeter, 10 g of ice melts with a heat of fusion of 334 J/g. How much heat is released?

jeka57 [31]

Answer:

No heat is released.

Explanation:

A substance absorbs heat when it melts.

The formula for the heat absorbed is

$q = m\Delta_{\text{fus}}H$

Data:

m = 10 g

\Delta_{fus) H=\text{334 J/g}

Calculations:

$q = 10 \times 334 = \text{3340 J = 3.34 kJ}\\\text{The ice }\boxed{\textbf{absorbs 3.34 kJ}} \text{ when it melts}.$

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2 years ago

If cats take over the world, will you make them extinct or be their slave.

prisoha [69]

Answer:

Make them go instinct

Explanation:

No one wants cats taking over the whole world

3 0

3 years ago

I WILL GIVE YOU BRAILEST!!!!!!!!!

Sholpan [36]

Answer:

atomic modifier

Explanation:

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6 0

3 years ago

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