Answer:
<h3>F=4k.gm/s^2</h3>
Explanation:
<h3>F=m×a</h3><h3>f=2k.g×2m/s^2</h3><h3>f=4k.gm/s^2</h3>
Answer:
ethanol
iupac stand for international union for pure and applied chemistry
According to Henderson–Hasselbalch Equation,
pH = pKa + log [Acetate] / [Acetic Acid]
As,
pKa = -log Ka
pKa = -log (1.8 × 10⁻⁵)
pKa = 4.74
So,
pH = 4.74 + log [Acetate] / [Acetic Acid]
4.34 = 4.74 + log [Acetate] / [Acetic Acid]
4.34 - 4.74 = log [Acetate] / [Acetic Acid]
-0.40 = log [Acetate] / [Acetic Acid]
Taking Antilog on both sides,
[Acetate] / [Acetic Acid] = 0.398
Answer:
As, the temperature decreased from 40.0 °C to 0.0 °C an amount will be recrystallized and precipitated as solid crystals in the water (51.0 g - 14.0 g = 37.0 g) and 14.0 g will be dissolved in water.
Explanation:
- Firstly, we must mention that:
The solubility of KNO₃ per 100.0 g of water at 40.0 °C = 63.0 g.
The solubility of KNO₃ per 100.0 g of water at 0.0 °C = 14.0 g.
- So, at 40.0 °C, 51.0 g of KNO₃ will be completely dissolved in water.
- <em>As, the temperature decreased from 40.0 °C to 0.0 °C an amount will be recrystallized and precipitated as solid crystals in the water (51.0 g - 14.0 g = 37.0 g) and 14.0 g will be dissolved in water.</em>
