This is an incomplete question, here is a complete question.
The Henry's law constant for oxygen dissolved in water is 4.34 × 10⁹ g/L.Pa at 25⁰C.If the partial pressure of oxygen in air is 0.2 atm, under atmospheric conditions, calculate the molar concentration of oxygen in air-saturated and oxygen saturated water.
Answer : The molar concentration of oxygen is, 
Explanation :
As we know that,
where,
= molar solubility of 
= ?
= partial pressure of = 0.2 atm = 1.97×10⁻⁶ Pa
= Henry's law constant = 4.34 × 10⁹ g/L.Pa
Now put all the given values in the above formula, we get:
Now we have to molar concentration of oxygen.
Molar concentration of oxygen = 
Therefore, the molar concentration of oxygen is,
Each particular chemical reaction cannot be expected to occur at identical rates.
True. Not all chemical reactions happen at the same rate, depending on the catalyst.
10 electrons
Explanation:
The maximum number of electrons in a single d-subshell is 10 electrons.
The d-notation stands for an azimuthal quantum number or secondary quantum number.
This subshell can only accommodate a maximum of 10 electrons.
d- subshell has five orbitals
Each orbital is able to accommodate 2 electrons.
Therefore 5 x 2 = 10 electrons
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Answer:
Explanation:
Hello,
In this case, by considering the given seminormal solution, we infer it is a 0.5-N solution which means that we can obtain the equivalent grams as shown below for the 55 cc (0.055 L) volume:
Next, since sodium carbonate has two sodium ions with a +1 oxidation state each, we can obtain the moles:
Finally, the mass is computed by using its molar mass (106 g/mol)
Regards.
Great Question!
The Answer Would Be "B" The "RESPONDING" Variable
