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ss7ja [257]
4 years ago
5

A pan containing 40 grams of water was allowed to cool from a temperature of 91.0C. If the amount of heat repressed is 1,300 jou

les what is the approximate final temperature of the water.
74 C
78C
81 C
83C
Chemistry
1 answer:
Vinvika [58]4 years ago
3 0

Answer:

83°C

Explanation:

The following were obtained from the question:

M = 40g

C = 4.2J/g°C

T1 = 91°C

T2 =?

Q = 1300J

Q = MCΔT

ΔT = Q/CM

ΔT = 1300/(4.2x40)

ΔT = 8°C

But ΔT = T1 — T2 (since the reaction involves cooling)

ΔT = T1 — T2

8 = 91 — T2

Collect like terms

8 — 91 = —T2

— 83 = —T2

Multiply through by —1

T2 = 83°C

The final temperature is 83°C

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5 0
3 years ago
What are some positive applications for allelotoxin?
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Positive applications for allelotoxin is that it prevents plants from enduring any type of competition with other species.

<h3>What is Allelopathy?</h3>

This is the process in which a plant inhibits the growth of another through a secretion of a chemical which is referred to as allelotoxin.

This technique however reduces biodiversity which isn't ideal so as to prevent organisms from going extinct and also reduces adaptation or evolution due to the reduced or non growth of the plant species which are affected.

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1 year ago
How are the elements arranged in the modern periodic table g?
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7 0
3 years ago
A lab technician needs to create 570.0 milliliters of a 2.00 M solution of magnesium chloride (MgCl2). To make this solution, ho
love history [14]

Answer:

108.3g

Explanation:

Given parameters:

Volume of solution = 570mm = 0.57L (1000mm = 1L)

Molarity of solution = 2M

Unknown

Mass of MgCl₂

Solution

We first find the  number of moles in the given concentration of magnessium chloride using the expression below:

       Number of moles of MgCl₂= Molarity x volume = 2 x 0.57 = 1.14moles

Using this known moles, we can the unknown mass of MgCl₂ the technician would require:

       Mass of MgCl₂ required = number of moles of MgCl₂ x molar mass

Molar mass of MgCl₂:

Atomic mass of Cl = 35.5g

Atomic mass of Mg = 24g

MgCl₂ = 24 + (35.5x2) = 95gmol⁻¹

Mass of MgCl₂ required = 1.14mole x 95gmole⁻¹ = 108.3g

7 0
3 years ago
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