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natulia [17]
3 years ago
7

Jatonia sold n cups of lemonade at her stand for 0.75 each. She made a total of 18.00. Write an equation to express how many cup

s of lemonade she sold.
Mathematics
2 answers:
jok3333 [9.3K]3 years ago
8 0
0.75n=18.00

You see, you would have to see how many cups she sold and by doing that you have to divide .75 by 18.00 to represent that you put n with the .75 and that causes you to need to get n alone so you divide .75 from 18 and get your answer
Luba_88 [7]3 years ago
6 0
$18 divided by $0.75 =24

She sold 24 cups of lemonade, and your equation looks like this:

$18 ÷ $0.75 = 24


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The sum of x and 8 is less than 72​
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Answer:

x<84

Step-by-step explanation:

First, write an inequality. We know it is not an equation because of the words "less than". Also, x and 8 are being added because of the word "and". Here's the inequality: x+8 < 72. Now, subtract 8 on both sides so x is isolated. Our simplified inequality looks like this: x < 84.

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3 years ago
50+51+52+...+101=...<br>Can you help me? I do not understand
Dmitriy789 [7]

Suppose

S=50+51+52+\cdots+100+101

At the same time, we can write

S^*=101+100+99+\cdots+51+50

Note that S=S^* (just reverse the sum). Let's pair the first terms of S and S^*, and the second, and the third, and so on:

S+S^*=(50+101)+(51+100)+(52+99)+\cdots+(100+51)+(101+50)

Now, each grouped term in the sum on the right side adds to 151. There are 52 grouped terms on that same side (because there are 50 numbers in the range of integers 51-100, plus 50 and 101), which menas

S+S^*=52\cdot151

But S=S^*, as we pointed out, so

2S=52\cdot151\implies S=\dfrac{52\cdot151}2=3926

5 0
3 years ago
What is the apparent solution to the system of equations?
Alexus [3.1K]
X = 3
y = -3

You will see this using any graphing tool at your disposal. 
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Jasmine earns $36 for 4 hours of baby-sitting. She charges a constant hourly rate. Compare the tables. Which correctly shows the
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The answer would be A. She charges $9 an hour.
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Read 2 more answers
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at
kari74 [83]

Answer: 5 km walking and 30 km by bus

Step-by-step explanation:

Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?

walking - 5km/h                                         bus - 60km/h

distance walking - d₁                                 distance bus - d₂

time walking - t₁                                         time bus - t₂

d₁ + d₂ = 35

t₁ + t₂ = 1.5

v = d/t

vwalking = d₁/t₁

5 = d₁/t₁ ⇒ d₁ = 5t₁

vbus = d₂/t₂

60 = d₂/t₂ ⇒ d₂ = 60t₂

d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35

_________________________

5t₁ + 60t₂ = 35

t₁ + t₂ = 1.5  (*-5)

5t₁ + 60t₂ = 35

-5t₁ -5t₂ = -7.5   (+)

__________________________

55t₂ = 27.5

t₂ = 27.5/55 = 0.5 h

t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h

d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km

d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km

6 0
3 years ago
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