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Ksju [112]
3 years ago
7

the taxi fare in new york city is $2.40 for the first 1/2 miles and additional mileage is charged at the rate $2.00 for each add

itional miles. you plan to give the driver a $2 tip
Mathematics
1 answer:
Licemer1 [7]3 years ago
6 0
You're forgetting to add how many miles did the taxi drove you, without it, this problem doesn't have a solution, you're not including how many miles were drove additionally, as well as how much money you carry in the first place bud sorry
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Find the value of x.
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99

Step-by-step explanation:

That quadrilateral equals to 360. So i had to add the numbers which equal 261. Then i did 360-261=99.

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The cost of one can of soda if 6 cans cost n
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if 6 cans cost n

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6 cans cost 12

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3 years ago
Which number could be multiplied by each side of the equation to produce the equivalent equation x = 10?
Liono4ka [1.6K]
5/4 could be multiplied by each side for x=10. D is your answer.
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3 years ago
Which polynomial equation is a valid identity?
yulyashka [42]

Answer:

D

Step-by-step explanation:

Expand factors using FOIL

A

(x + 1)² - x² = x² + 2x + 1 - x² = 2x + 1 ≠ 1 ← False

B

(5x - 2)² + 4 = 25x² - 20x + 4 + 4 = 25x² - 20x + 8 ≠ 25x² - 20x ← False

C

(x + 2y)(x - 2y) = x² - 4y² ≠ x² + 4xy - 4y² ← False

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4 0
3 years ago
Use the Chain Rule to find the indicated partial derivatives. u = x2 + yz, x = pr cos(θ), y = pr sin(θ), z = p + r; (partial u)/
devlian [24]

u(x,y,z)=x^2+yz

\begin{cases}x(p,r,\theta)=pr\cos\theta\\y(p,r,\theta)=pr\sin\theta\\z(p,r,\theta)=p+r\end{cases}

At the point (p,r,\theta)=(2,2,0), we have

\begin{cases}x(2,2,0)=4\\y(2,2,0)=0\\z(2,2,0)=4\end{cases}

Denote by f_x:=\dfrac{\partial f}{\partial x} the partial derivative of a function f with respect to the variable x. We have

\begin{cases}u_x=2x\\u_y=z\\u_z=y\end{cases}

The Jacobian is

\begin{bmatrix}x_p&x_r&x_\theta\\y_p&y_r&y_\theta\\z_p&z_r&z_\theta\end{bmatrix}=\begin{bmatrix}r\cos\theta&p\cos\theta&-pr\sin\theta\\r\sin\theta&p\sin\theta&pr\cos\theta\\1&1&0\end{bmatrix}

By the chain rule,

u_p=u_xx_p+u_yy_p+u_zz_p=2xr\cos\theta+zr\sin\theta+y

u_p(2,2,0)=2\cdot4\cdot2\cos0+4\cdot2\sin0+0\implies\boxed{u_p(2,2,0)=16}

u_r=u_xx_r+u_yy_r+u_zz_r=2xp\cos\theta+zp\sin\theta+y

u_r(2,2,0)=2\cdot4\cdot2\cos0+4\cdot2\sin0+0\implies\boxed{u_r(2,2,0)=16}

u_\theta=u_xx_\theta+u_yy_\theta+u_zz_\theta=-2xpr\sin\theta+zpr\cos\theta

u_\theta(2,2,0)=-2\cdot4\cdot2\cdot2\sin0+4\cdot2\cdot2\cos0\implies\boxed{u_\theta(2,2,0)=16}

7 0
3 years ago
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