Question

Captain Tiffany has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Omar and his merciless band of thieves. The Captain has probability \dfrac{1}{2} 2 1 ​ start fraction, 1, divided by, 2, end fraction of hitting the pirate ship. The pirate only has one good eye, so he hits the Captain's ship with probability \dfrac{2}{7} 7 2 ​ start fraction, 2, divided by, 7, end fraction. If both fire their cannons at the same time, what is the probability that both the pirate and the Captain hit each other's ships?

Answer 1

Answer:

1/7

Step-by-step explanation:

The probability that the Captain hits is \dfrac{1}{2}

2

1

​

start fraction, 1, divided by, 2, end fraction.

The probability that the pirate hits is \dfrac{2}{7}

7

2

​

start fraction, 2, divided by, 7, end fraction.

1/2 x 2/7 = 1/7