All categories

3 years ago

Please help asap:) 30points

Mathematics

2 answers:

pishuonlain [190]3 years ago

8 0

Answer:

q#1 Option B.2 possible solution is correct option

Q#2 option c. 1 viable solution is correct option.

Step-by-step explanation:

Q#1

y=4 $x^{2}$ +3x+45

as this is a quadratic solution

and we know that when we solve a quadratic equation then it gives two possible solutions

hence option b is the correct option

Q#2

option c is correct option when we solve an quadratic equation it gives two solution one is positive and other is negative as we know that income cannot be negative

hence only one viable solution exists when we solve this

y=4 $x^{2}$ +3x+45 quadratic equation

Rasek [7]3 years ago

7 0

Answer:

q#1 Option B.2 possible solution is correct optionQ#2 option c. 1 viable solution is correct option. Step-by-step explanation:Q#1y=4+3x+45as this is a quadratic solution and we know that when we solve a quadratic equation then it gives two possible solutions hence option b is the correct optionQ#2option c is correct option when we solve an quadratic equation it gives two solution one is positive and other is negative as we know that income cannot be negative hence only one viable solution exists when we solve this y=4+3x+45 quadratic equation

Step-by-step explanation:

Q#1y=4+3x+45as this is a quadratic solution and we know that when we solve a quadratic equation then it gives two possible solutions hence option b is the correct option Q#2option c is correct option when we solve an quadratic equation it gives two solution one is positive and other is negative as we know that income cannot be negative hence only one viable solution exists when we solve this y=4+3x+45 quadratic equation

You might be interested in

Solve (x + 3)2 + (x + 3) – 2 = 0. Let u = Rewrite the equation in terms of u. (u2 + 3) + u – 2 = 0 u2 + u – 2 = 0 (u2 + 9) + u –

Verdich [7]

Answer:

The solutions of the original equation are x=-5 and x=-2

Step-by-step explanation:

we have

$(x+3)^2+(x+3)-2=0$

Let

$u=(x+3)$

Rewrite the equation

$(u)^2+(u)-2=0$

Complete the square

$u^2+u=2$

$u^2+u+1/4=2+1/4$

$u^2+u+1/4=9/4$

rewrite as perfect squares

$(u+1/2)^2=9/4$

square root both sides

$(u+1/2)=\pm\frac{3}{2}$

$u=(-1/2)\pm\frac{3}{2}$

$u=(-1/2)+\frac{3}{2}=1$

$u=(-1/2)-\frac{3}{2}=-2$

the solutions are

u=-2,u=1

<em>Alternative Method</em>

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$(u)^2+(u)-2=0$

$a=1\\b=1\\c=-2$

substitute in the formula

$u=\frac{-1\pm\sqrt{1^{2}-4(1)(-2)}} {2(1)}$

$u=\frac{-1\pm\sqrt{9}} {2}$

$u=\frac{-1\pm3} {2}$

$u=\frac{-1+3} {2}=1$

$u=\frac{-1-3} {2}=-2$

the solutions are

u=-2,u=1

<em>Find the solutions of the original equation</em>

For u=-2

$-2=(x+3)$ ----> $x=-2-3=-5$

For u=1

$1=(x+3)$ ----> $x=1-3=-2$

therefore

The solutions of the original equation are

x=-5 and x=-2

4 0

3 years ago

Read 2 more answers

Please help i put 15 points for this

Arturiano [62]

Answer:

The first & the third are true.

Step-by-step explanation:

If you put the equation on the calculator, you'll get that x=1 then, the equation divides by (x-1) and has a remainder =0 & (x-1) is a factor of the equation since it gives a remainder=0

5 0

3 years ago

(8+5i) + (10+6i)-(3+6i)

Natali [406]

Answer:

15 + 5i

Step-by-step explanation:

$(8+5i) + (10+6i)-(3+6i) \\ \\ = 8 + 5i + 10 + 6i - 3 - 6i \\ \\ =( 8 + 10 - 3 )+ (5i + 6i - 6i )\\ \\ = 15 + 5i$

8 0

3 years ago

Pls help me

andrezito [222]

Step-by-step explanation:

the answer is in the picture

4 0

3 years ago

Help please........number 5 and 7

fiasKO [112]

Answer:

5. r(x) is f(x) translated down 16 units

7. g(x) is f(x) vertically scaled by a factor of 2/5

Step-by-step explanation:

5. Adding a number to a function value translates that value up by the amount of the number. If the number is negative, the translation is downward. Adding -16 to x^2 translates the graph down 16 units.

___

7. Multiplying a function value vertically scales the graph of the function by the multiplying factor. For factors greater than 1, the result is a vertical expansion; for factors less than 1, the result is vertical compression. Here, the function f(x) = x^2 is multiplied by 2/5, so the resulting g(x) is vertically scaled by a factor of 2/5 (compressed).

For a parabola, the effect is to make the graph appear "wider." Values some distance from the line of symmetry that would have been vertically off the page now appear on the page. Hence, the horizontal extent of the graph on the page has increased.

6 0

3 years ago