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bagirrra123 [75]
3 years ago
5

2/3 k =28•4/9 solve for k

Mathematics
2 answers:
rodikova [14]3 years ago
6 0
The answer is, k=18.
Andre45 [30]3 years ago
3 0
K=18 do you know you can get the answer for the Internet right
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8. A 140-pound female has three mixed drinks one right after the other.
Sonja [21]

The BAC of the female is an illustration of proportion

  • The BAC after consuming the three drinks is 0.029w
  • The BAC three hours after consuming the drinks is 0.087 w

<h3>How to calculate the BAC?</h3>

BAC is calculated using:

BAC = Alcohol consumed/(Body Weight * R)

The weight is given as:

Body weight = 140 lb

Convert to kg

Body weight = 63.5 kg

For female

R = 0.55

So, we have:

BAC = Alcohol/(63.5 * 0.55)

BAC = Alcohol/34.925

BAC = 0.029Alcohol

The weight or volume of the alcohol consumed is given.

So, we represent it with w.

BAC = 0.029w

Hence, the BAC after consuming the three drinks is 0.029w

<h3>How to calculate the BAC after 3 hours?</h3>

We have:

BAC1 = 0.029w

Time (t) = 3 hours

The BAC after 3 hours is

BAC = BAC1 * (t - 0.015)

So, we have:

BAC = 0.029w * (3 - 0.015)

Evaluate the product

BAC = 0.087w

Hence, the BAC three hours after consuming the drinks is 0.087 w

Read more about BAC at:

brainly.com/question/1781657

7 0
2 years ago
Using the given zero, find one other zero of f(x). Explain the process you used to find your solution.
IRISSAK [1]

Answer:

One other zero is 2+3i

Step-by-step explanation:

If 2-3i is a zero and all the coefficients of the polynomial function is real, then the conjugate of 2-3i is also a zero.

The conjugate of (a+b) is (a-b).

The conjugate of (a-b) is (a+b).

The conjugate of (2-3i) is (2+3i) so 2+3i is also a zero.

Ok so we have two zeros 2-3i and 2+3i.

This means that (x-(2-3i)) and (x-(2+3i)) are factors of the given polynomial.

I'm going to find the product of these factors (x-(2-3i)) and (x-(2+3i)).

(x-(2-3i))(x-(2+3i))

Foil!

First: x(x)=x^2

Outer: x*-(2+3i)=-x(2+3i)

Inner:  -(2-3i)(x)=-x(2-3i)

Last:  (2-3i)(2+3i)=4-9i^2 (You can just do first and last when multiplying conjugates)

---------------------------------Add together:

x^2 + -x(2+3i) + -x(2-3i) + (4-9i^2)

Simplifying:

x^2-2x-3ix-2x+3ix+4+9  (since i^2=-1)

x^2-4x+13                     (since -3ix+3ix=0)

So x^2-4x+13 is a factor of the given polynomial.

I'm going to do long division to find another factor.

Hopefully we get a remainder of 0 because we are saying it is a factor of the given polynomial.

                x^2+1

              ---------------------------------------

x^2-4x+13|  x^4-4x^3+14x^2-4x+13                    

              -( x^4-4x^3+ 13x^2)

            ------------------------------------------

                                 x^2-4x+13

                               -(x^2-4x+13)

                               -----------------

                                    0

So the other factor is x^2+1.

To find the zeros of x^2+1, you set x^2+1 to 0 and solve for x.

x^2+1=0

x^2=-1

x=\pm \sqrt{-1}

x=\pm i

So the zeros are i, -i , 2-3i , 2+3i

7 0
3 years ago
HEELLLP LIKE RIGHT NOW! PLSSS
swat32
Do you have to multiply?
3 0
2 years ago
Please help:<br> In PQR, sin P=64, sin R=35, and r=21. Find the length of p.
son4ous [18]

Answer:

32.9 units

Step-by-step explanation:

p/sinP = r/sinR

p = sinP × r/sinR

p = sin(64) × 21/sin(35)

p = 32.9069916

5 0
3 years ago
Pls find the surface area for me. I need help ASAP!
melomori [17]

Answer:

About 90.84 in^2

Step-by-step explanation:

The formula for the surface area of a pyramid is

lw+l\sqrt{\frac{w}{2}^2+h^2}+w\sqrt{\frac{l}{2}^2+h^2}, which for this pyramid is equal to about 90.84 in^2. Hope this helps!

3 0
3 years ago
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