3 years ago

Anyone waanna talk on Instagram

Mathematics

2 answers:

Maslowich3 years ago

8 0

Ok sure and one more thing are you smart at geometry like 100% smart

hodyreva [135]3 years ago

7 0

Answer:

drowning._.welp

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mezya [45]

Answer:

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Step-by-step explanation:

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2 years ago

HELP!!Find the eighth term of the sequence given by the rule tn = -3n + 10

Soloha48 [4]

tn=-3n+10

Substitute 8th term for n into the equation.

tn=-3(8)+10

Multiply the bracket first

=-24+10

tn=-14

Answer: b

I think this is the right answer.

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4 years ago

Write the quadratic equation y = x2- 6x + 7 in vertex form

Sedbober [7]

Answer:

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Step-by-step explanation:

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3 years ago

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Olin [163]

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3 years ago

I really dont know how to start this Calculus 1 question!

hichkok12 [17]

According to the given plot, $f'(1)=2$ . Then the linear approximation to $f(x)$ at $x=1$ is

$L(x)=f(1)+f'(1)(x-1)=6+2(x-1)=2x+4$

Then

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$f(1.05)\approx L(1.05)=6.1$

On the interval [0, 1], the plot of $f'(x)$ is positive, so $f(x)$ is an increasing function here. But we can see that $f'(x)$ is approaching 0. This means tangent lines to $f(x)$ have a positive slope, but the slopes are approaching 0 and are thus becoming less steep. This in turn means the tangent lines lie above the curve, so the approximations are greater than the actual values of $f(0.95)$ and $f(1.05)$ .

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3 years ago

Anyone waanna talk on Instagram ​

Anyone waanna talk on Instagram