Both of these conditions must be true in order for the assumption that the binomial distribution is approximately normal. In other words, if 
and 
then we can use a normal distribution to get a good estimate of the binomial distribution. If either np or nq is smaller than 5, then a normal distribution wouldn't be a good model to use.
side note: q = 1-p is the complement of probability p
Answer:
hell have 700 dollars plus the 10 dollars in his savings
Step-by-step explanation:
Answer:
Step-by-step explanation:
Q no 4 :
4, 8
1, 5
3, 7
2, 6
Q no 5:
(a)
10x + 1 = 12x - 5
1+5= 12x - 10x
2x = 6
x = 6/2
x = 3
(b)
11x - 15 + 5x - 13 = 180 (angles on a straight line)
11x + 5x - 15 - 13 =180
16x - 27 = 180
16x = 180 + 27
16x = 207
x = 207 / 16
x = 12.9375
Answer:
(x-4)^2-9 where a=4 and b=9
Step-by-step explanation:
x^2-8x+5
x^2-8x+16-16+5
(x-4)^2-9, a=4 and b=9
