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Xelga [282]
4 years ago
12

A circular conducting loop of radius 23.0 cm is located in a region of homogeneous magnetic field of magnitude 0.500 T pointing

perpendicular to the plane of the loop. The loop is connected in series with a resistor of 265 Ω. The magnetic field is now increased at a constant rate by a factor of 2.50 in 23.0s. Calculate the magnitude of the induced emf in the loop while the magnetic field is increasing.
Physics
1 answer:
Alchen [17]4 years ago
4 0

Answer:

The magnitude of the induced emf is

Ф = 5.419 x 10⁻³ V

Explanation:

Given:

r = 23.0 cm = 0.23 m

β₁ = 0.50 T

β₂ = 2.50 * 0.50 T = 1.25 T

Calculate the magnitude of the induced emf the magnetic field is increasing

Ф = A * Δβ / Δt

A = π * r² = π * 0.23² m = 0.166 m²

Ф = 0.166m² * (1.25 - 0.5) T / 23 s

Ф = 5.419 x 10⁻³ V

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REY [17]

Answer:

Part a)

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Explanation:

As we know that the magnetic field near the center of the solenoid is given as

B = \mu_0 ni

Also we know by  equation of Faraday's law

EMF induced in the closed loop will be equal to rate of change in magnetic flux

so we have

EMF = A\frac{dB}{dt}

so we have

\int E. dL = \pi r^2 (\mu_0 n \frac{di}{dt})

E. (2\pi r) = \pi r^2 (\mu_0 n \frac{di}{dt})

E = \frac{\mu_0 n r}{2} \frac{di}{dt}

Part a)

At r = 0.500 cm

we have

E = \frac{4\pi \times 10^{-7} (950) (0.500 \times 10^{-2})}{2}(63)

E = 0.188 \times 10^{-3} N/C

Part b)

At r = 1.00 cm

we have

E = \frac{4\pi \times 10^{-7} (950) (1.00 \times 10^{-2})}{2}(63)

E = 0.376 \times 10^{-3}N/C

5 0
3 years ago
Usually, when the temperture is increased l, what will happen to the ratevof dissolving?
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3 years ago
True or False? There is more downward force on a faster car than on a slower car when both
kondor19780726 [428]

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false

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3 0
3 years ago
1. You are designing a new solenoid and experimenting with material for each turn. The particular turn you are working with is a
svetoff [14.1K]

Answer:

Explanation:

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= μ₀I / 2r

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= 4π x 10⁻⁷ x 15 / (2 x 3.5 x 10⁻²)

= 26.9 x 10⁻⁵ T

2 )

Negative z direction .

The direction of magnetic field due to a circular coil having current is known  

with the help of screw rule or right hand thumb rule.

3 )

If we decrease the radius the magnetic field will:__increase _____.

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4 0
3 years ago
A current of 16.0 mA is maintained in a single circular loop of 1.90 m circumference. A magnetic field of 0.790 T is directed pa
AVprozaik [17]

To solve this problem it is necessary to take into account the concepts related to the magnetic moment and the torque applied over magnetic moments.

For the case of the magnetic moment of a loop we have to,

\mu = IA

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Moreover the torque exerted by the magnetic field is defined as,

\tau = IAB

Where,

I = Current

A = Area of the loop

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r = \frac{P}{2\pi}

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\mu = 4.58*10^{-3} A.m^2

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\tau = (16*10^{-3})(0.287)(0.790)

\tau = 3.62*10^{-3}Nm

Therefore the torque exerted by the magnetic field is 3.62*10^{-3}Nm

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3 years ago
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