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2 years ago

Sodium chloride and calcium carbonate combine to form sodium carbonate and calcium chloride in the reversible reaction.

Physics

2 answers:

lidiya [134]2 years ago

6 0

Answer:

I think is Number 2

The rate at which calcium chloride is equal to the rate at which sodium chloride is produced.

Let me know if I'm wrong.

QveST [7]2 years ago

4 0

The statement that is necessarily correct about the reaction is that both calcium carbonate and sodium carbonate are being produced

2NaCl + CaCO3 ⇌ Na2CO3 + CaCl2

The reaction above is a reversible reaction. A reversible reaction is a reaction in which the conversion of reactant to products and the conversion from product to reactant occurs simultaneously. This reaction is just like a back and forth reaction.

⇌ symbol represents a reversible reaction. Therefore, the statement that is necessarily correct about the reaction is that both calcium carbonate and sodium carbonate are being produced

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The membrane of a living cell can be approximated by a parallel-plate capacitor with plates of area 4.50×10−9 m2 , a plate separ

Marizza181 [45]

The energy stored in the membrane is $6.44\cdot 10^{-14} J$

Explanation:

The capacitance of a parallel-plate capacitor is given by

$C=\frac{k\epsilon_0 A}{d}$

where

k is the dielectric constant of the material

$\epsilon_0$ is the vacuum permittivity

A is the area of the plates

d is the separation between the plates

For the membrane in this problem, we have

k = 4.6

$A=4.50\cdot 10^{-9} m^2$

$d=8.1\cdot 10^{-9} m$

Substituting, we find its capacitance:

$C=\frac{(4.6)(8.85\cdot 10^{-12})(4.50\cdot 10^{-9})}{8.1\cdot 10^{-9}}=2.26\cdot 10^{-11} F$

Now we can find the energy stored: for a capacitor, it is given by

$U=\frac{1}{2}CV^2$

where

$C=2.26\cdot 10^{-11} F$ is the capacitance

$V=7.55\cdot 10^{-2} V$ is the potential difference

Substituting,

$U=\frac{1}{2}(2.26\cdot 10^{-11} F)(7.55\cdot 10^{-2})^2=6.44\cdot 10^{-14} J$

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3 years ago

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A 3.0kg weight W is initially at rest on incline AB, which is raised 40° above the horizontal. The effective coefficient is

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(a) The acceleration of the system is determined as 1.58 m/s².

(b) The relative weight of P is pounds is determined as 0.14 lb.

<h3>Acceleration of the system</h3>

The acceleration of the system is calculated as follows;

W - T = m₂a --- (1)

T = m₁a ----(2)

μmgsinθ - m₁a = m₂a

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