What are the similarities between EMS waves and mechanical waves?

What is the independent variable and why?

valina [46]

The independent variable is how long the egg takes to cook

4 0

3 years ago

You are driving your 1700 kg car at 21 m/s down a hill with a 5.0∘ slope when a deer suddenly jumps out onto the roadway. You sl

podryga [215]

Answer:

d = 27.7 m

Explanation:

Here the car is driving on the inclined plane

So here we can say that work done by the gravity and work done by friction is equal to change in kinetic energy of the system

So here we can write it as

$mgsin\theta \times d - F_f \times d = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2$

now we have

m = 1700 kg

$v_f = 0$

$v_i = 21 m/s$

$F_f = 1.5 \times 10^4 N$

$(1700)(9.81)sin5 (d) - (1.5\times 10^4)d = 0 - \frac{1}{2}(1700)(21^2)$

$1453.5 d - (1.5\times 10^4)d = -374850$

$d = 27.7 m$

6 0

3 years ago

The higher the pressure on a liquid, the higher its boiling point temperature. true false

Alika [10]

True, p1/t1=p2/t2. Pressure is related to temperature at which it boils so pressure does affect the boiling point.

3 0

3 years ago

Read 2 more answers

Robert, a stuntman, projects himself from a height of 50.0 meters in a horizontal direction. He safely lands at a horizontal dis

Olin [163]

To get this we need to know how long he was traveling. To know that we need to solve for the time it took for him to hit the ground. This is given by the vertical height he started at and the equation of motion for falling objects. The position function is
Y= -(9.8/2)t^2 + 50 = 0
t=3.19s
That's how long he's in the air. When he hits the ground he stops moving forward so this is also the amount of time he was moving at 100m/s horizontally. Now use speed distance relationship
X=vt
And solve for v
100m/3.19s = 31.35m/s

3 0

4 years ago

Read 2 more answers

The Space Shuttle does not directly inject into its prescribed mission orbit. Rather, themain engine shutdown occurs at the apog

iris [78.8K]

Answer:

(a) burnout speed at apogee in the external tank disposal orbit=7.82 km/sec

(b) ΔV required for the OMS-1 =0.066 km/sec

(c) ΔV required for the OMS-2 =0.045 km/sec

(d) This part of the question is explained in detailed way in the attached file.

Explanation:

Detailed explanation of all the parts of the question are given in attached files.