Find two numbers that have 2, 3, and 5 as factors. What other factors do those two numbers have in common?

1 answer:

4 0

To find the first number, just multiply the three numbers together.
$2*3*5 \\ 6*5 \\ 30$

To find the second number, multiply the three numbers together along with another number (this number can be anything).
$2*3*5*4 \\ 6*5*4 \\ 30*4 \\ 120$

What They Have in Common:
- All numbers will be even, since you are multiplying by 2.
- All numbers will end in a zero, since you are multiplying by 5 and also 2.

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Please Help!!!!

Iteru [2.4K]

Step-by-step explanation:

Given : m∥n , ∠1= 50° , ∠2= 48° , and line s bisects ∠ABC

To prove = ∠3= 49°

Solution:

In figure, m∥n cut by traversal t.

So, ∠DEF = ∠ABC(alternative exterior angles)

∠1 + ∠2 = ∠4 + ∠5

∠ABC = ∠1 + ∠2 = 50° + 48° = 98°

Also given that s bisect angles ∠ABC.

∠4 = ∠5

∠ABC = ∠4 + ∠5 = 98°

∠4 + ∠4 = 98°

2∠4 = 98°

∠4 = 49°

∠4= ∠3 = 49° (vertically opposite angles)

∠3 = 49° ,hence proved

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3 years ago

What is measure of angle R?

Oliga [24]

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3 years ago

denis23 [38]

Answer:

$B = 325$