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3 years ago

Please helppp number 11

Mathematics

1 answer:

aivan3 [116]3 years ago

4 0

Answer:

(1/3)⁷

Step-by-step explanation:

negative exponents work like this:

x⁻²=(1/x)²

Apply this theory to this equation:

3⁻⁷=

(1/3)⁷

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If food has 5g fat, 10g protein and 20g carbs, how many calories is it (9,4,4)?

abruzzese [7]

Answer:

165 Calories

Step-by-step explanation:

A gram of carbohydrate contains 4 calories. A gram of protein also contains 4 calories. A gram of fat, though, contains 9 calories

5x9=45 10x4=40 20x4=80 45+40+80= 165

3 0

3 years ago

Read 2 more answers

Please help...its for Delta math. will mark brainliest and I will be ur friend♥<br>

REY [17]

The exponential functions change is represented by decay and the percentage rate of decrease is 1.00619%.

Step-by-step explanation:

Step 1:

To determine if the function represents growth or decay, we substitute values to x.

If the values increase with an increase of x, it represents growth.

If the values decrease with an increase of x, it represents decay.

Step 2:

If $x= 10,$ $y = 1,300 (\frac{1}{2})^{\frac{10}{69} } = 1,300 (0.9044) = 1,175.72.$

If $x=11,$ $y = 1,300 (\frac{1}{2})^{\frac{11}{69} } = 1,300 (0.8953) = 1,163.89.$

So as x increases the value of y decreases, so it represents decay.

Step 3:

The percentage rate of change is determined by dividing the difference of two consecutive values by the first value.

The percentage rate of change $= \frac{y(x=11) - y(x=10)}{y(x=10)}.$

Substituting the values, we get

The percentage rate of change $=\frac{1,175.72-1,163.89}{1,175.72}(100) = 1.00619\%$ .

As the values of y decrease with an increase in x, it is the percent decrease per unit.

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4 years ago

Read 2 more answers

Working together, it takes two different sized hoses 35 minutes to fill a small swimming pool. If it takes 60 minutes for the la

almond37 [142]

L = rate of the large hose

S = rate of the small hose

we know the sum of their rates deliver the swimming pool filled up in 35 minutes, thus L + S = 35.

now, the large hose can do it in 60 minutes, that means that in 1 minute, the large hose has only done 1/60 th of the work.

the small hose can do the whole thing in S minutes, that means in 1 minute it has only done 1/S th of the whole work.

and since both of them working together can do it in 35 minutes, then in 1 minute they both have done 1/35 th of the whole job.

$\bf \stackrel{\textit{large's rate in 1 minute}}{\cfrac{1}{L}}+\stackrel{\textit{small's rate in 1 minute}}{\cfrac{1}{S}}=\stackrel{\textit{done in 1 minute}}{\cfrac{1}{35}} \\\\\\ \cfrac{1}{60}+\cfrac{1}{S}=\cfrac{1}{35}\implies \cfrac{S+60}{60S}=\cfrac{1}{35}\implies 35S+2100=60S\implies 2100=25S \\\\\\ \cfrac{2100}{25}=S\implies 84=S$