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3 years ago

15

Factor 15a^3+ 20a^2- 6a- 8 by grouping

1 answer:

Aleksandr [31]3 years ago

8 0

$15a^3+ 20a^2- 6a- 8$
= $5a^2(3a+ 4) - 2(3a + 4)$
= $(3a+ 4) (5a^2- 2)$

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A store sells flower arrangements at a cost of $28 each. Which statements are true regarding the price of the arrangements? Chec

Maru [420]

Let's check each case to determine the solution to the problem.

we know that

The cost of each flower arrangements is $\$28$

Statements

<u>case A)</u> If the price is marked down by $10$ percent, the new price will be $\$25.20$

we know that

If the price is marked down by $10$ percent

then

the new price will be

$10\%= \frac{10}{100} =0.10$

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$\$25.20=\$25.20$

therefore

The statement case A) is True

<u>case B)</u> If the price is marked down by $25$ percent, the new price will be $\$21$

we know that

If the price is marked down by $25$ percent

then

the new price will be

$25\%= \frac{25}{100} =0.25$

$(1-0.25)*\$28=0.75*\$28 \\= \$21$

$\$21=\$21$

therefore

The statement case B) is True

<u>case C)</u> If the price is marked down by $50$ percent, the new price will be $\$19$

we know that

If the price is marked down by $50$ percent

then

the new price will be

$50\%= \frac{50}{100} =0.50$

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$\$14 \neq \$19$

therefore

The statement case C) is False

<u>case D)</u> If the price is marked down by $35$ percent, the new price will be $\$18.20$

we know that

If the price is marked down by $35$ percent

then

the new price will be

$35\%= \frac{35}{100} =0.35$

$(1-0.35)*\$28=0.65*\$28 \\= \$18.20$

$\$18.20=\$18.20$

therefore

The statement case D) is True

<u>case E)</u> If the price is marked down by $40$ percent, the new price will be $\$29.80$

we know that

If the price is marked down by $40$ percent

then

the new price will be

$40\%= \frac{40}{100} =0.40$

$(1-0.40)*\$28=0.60*\$28 \\= \$16.80$

$\$16.80 \neq \$29.80$

therefore

The statement case E) is False

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