Answer:
a.8y³-6y
taking common
<u>2y(4y²-3)</u>
is a required answer
b.
3x²-20x+12
doing middle term factorization
3x²-18x-2x+12
3x(x-6)-2(x-6)
<u>(x-6)(3x-2)</u>
<u>is</u><u> </u><u>a</u><u> </u><u>required</u><u> </u><u>answer</u><u> </u><u>.</u>
They would be 69 and 70.
Your equation would be x + (x + 1) = 139
X would be the first integer and x + 1 would be the second
You would then solve the equation to get x as 69
X + 1 would then be 70
64/4 is 16 if that's what you meant.
Answer:
= 1 5/16
[/tex] 1 \frac{5}{16}[/tex]
Step-by-step explanation:

Expand

Collect like terms and simplify

Cross Multiply

Divide both sides of the equation by 80
