Answer:
11.4 years
Step-by-step explanation:
We assume you want to know the time it takes for Lucy's investment of $1200 to have a value of $6400. The compound interest formula is good for finding that.
FV = P(1 +r/n)^(nt)
for principal P invested at rate r per year for t years, compounded n times per year. We want to find t such that ...
6400 = 1200(1 +0.15/4)^(4t)
16/3 = 1.0375^(4t) . . . . divide by 1200
log(16/3) = 4t·log(1.0375) . . . . take logarithms
t = log(16/3)/(4·log(1.0375)) ≈ 11.4
It will take about 11.4 years for Lucy's investment value to be $6400.
The first one is fraction and the second one is volume.
Answer:
y = 9x/5 + 50
Step-by-step explanation:
We are represent the information as coordinate (x,y)
If the cost for an order of 100 kilograms of steel bars is $230, this is expressed as (100, 230)
Also if the cost for an order of 150 kilograms of steel bars is $320, this is expressed as;
(150, 320)
Find the equation of a line passing through the points. The standard form of the equation is expressed as y = mx+c
m is the slope
c is the intercept
Get the slope;
m = y2-y1/x2-x1
m = 320-230/150-100
m = 90/50
m = 9/5
Get the y-intercept by substituting m = 9/5 and any point say (100, 230) into the expression y = mx+c
230 = 9/5(100)+c
230 = 9(20)+c
230 = 180 + c
c = 230-180
c = 50
Get the required equation
y = mx+c
y = 9/5 x + 50
Hence an equation for the cost of an order of steel bars (y) in terms of the weight of steel bars ordered (x) is y = 9x/5 + 50
Answer:
117.00
Step-by-step explanation:
I = prt where i is the interest , p is the principal r is the rate and t is the time in years
2 years 6 months is 2.5 years
I = 1200 * .039* 2.5
I =117
Answer:
uh 52
Step-by-step explanation:
I say 52 cause like it sounds about reasonable
