Evaluate absolute value first.
|-4|=4
|2|= 2
Rewrite equation
3-4-2
-1-2
-3
Final answer: -3
Answer:
or 2/9
Step-by-step explanation:
Any single digit integer over 9 is the same as the integer repeating in decimals.
the standard form for a horizontal ellipse is
X^2/a^2 + y^2/b^2 = 1
Substitute 54 for b and and use (8,18) as the
point to find a
x=8
y=18
8^2/a^2 + 18^2/54^2 =1
64/a^2 + 324/2916 = 1
324/2916 reduces to 1/9
64/a^2 + 1/9 = 1
64/a^2= 1-1/9
64/a^2 = 8/9
64*9/8 = a^2
576/8 = 72
A^2 = 72
A = square root(72) = 8.485
So formula
would be x^2/72 + y^2/2916 =1
Answer:
The given equation will have value less than 100 whenever the value of b is greater than 12.89
Step-by-step explanation:
For the given equation, p(b) = 520 ×
to have a value less than 100 we can establish inequality as:
p(b) < 100
or, 520 ×
< 100
or,
×
< 
or,
< 
or, ㏒ (
) < ㏒ (
)
or, b× ㏒ 0.88 < ㏒ (
)
or,
< b
or, 12.89 < b
Hence for the equation to have value less than 100, b must be greater than 12.89.