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olya-2409 [2.1K]
3 years ago
7

0.0487 mg + 0.05834 mg + 0.00327 mg

Chemistry
1 answer:
ivolga24 [154]3 years ago
6 0
0.11031 mg
I think that is the answer
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Percent of water in Na2CO3 • 10H2O
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Hey there! 

In order to solve for the percentage of water in the compound, you will first need to find its total molar mass. You can do this by adding up the molar masses of each individual element in the compound. Then, you will divide the mass that you find of the water molecules by the total mass to get the percentage. 

→ Na₂CO₃ ×<span> 10 H</span>₂<span>O

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Now, just add all of those numbers up for the total molar mass. 

→ 45.9796 + 12.0107 + 47.997 + 180.15 = <span>286.1373
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Your answer will be about 63%. 

Hope this helped you out! :-)
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Explanation -

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