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Lerok [7]
1 year ago
6

You are given 100 g of a compound. The compound is composed of 37% hydrogen and 63% oxygen. How many grams oxygen are present in

the 100 g sample? Select one: a. 37 g b. 100 g c. 27 g d. 63 g
Chemistry
1 answer:
USPshnik [31]1 year ago
7 0

mass_{oxygen} = \%mass_{oxygen} \times mass_{compound} \\ m = 63\%(100) \\ m = 0.63(100) \\ m = 63 \: grams

<h2>Option d</h2>
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6. dissolving ice tea mix in water
Cloud [144]

Answer:

Dissolving ice tea mix in water is a chemical change

Explanation:

It is a chemical change because you can not bring back the ice tea mix back if you mix it in water.

Hope it helps

6 0
3 years ago
The reaction of a Lewis acid with a Lewis base would most likely be accompanied by an increase in which item?
Leokris [45]

The correct option is COVALENT BONDS.

A Lewis acid is defined as a substance which accept a pair of electron while a Lewis base refers to a substance that donate an unshared pair of electrons to another chemical specie with which it shared the donated pair of electrons.

Lewis acid and Lewis base react together to form salt and water. This type of reaction is called neutralization reaction. The neutralization reaction of Lewis acid and Lewis base involves electron pairs transfer, thus, there is an increase in the number of covalent bonds during this reaction.

5 0
3 years ago
Read 2 more answers
Please answer. Brainliest!
vichka [17]

Answer:

the equation is unbalanced

5 0
3 years ago
How many molecules of H2O and O2 is present in 8.5g of H2O?​
Igoryamba

Answer:

2.8 x 10²³ molecules H₂O

1.4 x 10²³ molecules O₂

Explanation:

First, you will need the balanced chemical equation for the formation of water:

2H₂ + O₂ -> 2H₂O

This will help in determining the mole ratios between water and oxygen, which we will need later.

Let's first calculate the number of H₂O (water) molecules. This will require stoichiometry. We are also given the mass, so we must convert mass into moles, then moles into molecules. mass -> moles -> molecules

8.5 g H₂O x (1 mol H₂O/18.01528 g H₂O) x (6.02 x 10²³ molecules H₂O/1 mol H₂O) = 2.8404 x 10²³ molecules H₂O

Rounded to 2 significant digits: 2.8 x 10²³ molecules H₂O

Now, to find the molecules of water, we can begin with the same stoichiometric equation, but before we convert to molecules, we will have to convert moles of water to moles of oxygen. This is where we will use the mole ratio of water to oxygen we got from the balanced chemical equation earlier. 2H₂O:1O₂

8.5 g H₂O x (1 mol H₂O/18.01528 g H₂O) x (1 mol O₂/2 mol H₂O) x (6.02 x 10²³ molecules O₂/1 mol O₂) = 1.4202 x 10²³ molecules O₂

Rounded to 2 significant digits: 1.4 x 10²³ molecules O₂

3 0
3 years ago
why is it better to use several trials of a titration rather than one trial to determine the concentration of a solution of unkn
svlad2 [7]
Because you are never 100% precise during the work, so it's best and most accurate answer is always the average of more trials. basically the more you do, the more accurate the answer shall be 
6 0
2 years ago
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