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sergeinik [125]
4 years ago
14

Suppose two students need to prepare three solutions, each one-half as concentrated as the previous, from a stock solution. (a)

One student dilutes 10 mL stock solution to a final volume of 20 mL. S/he dilutes 10 mL stock solution to a final volume of 40 mL. S/he dilutes 10 mL stock solution to a final volume of 60 mL. Does s/he have the solutions at the concentrations desired
Chemistry
1 answer:
Marianna [84]4 years ago
4 0

Answer:

Explanation:

When a solution is diluted ,its strength is decreased according to following

formula

S₁V₁ =S₂V₂

So when volume is doubled , strength becomes half .  One student dilutes 10 mL stock solution to a final volume of 20 mL. Its strength becomes half .

When S/he dilutes 10 mL stock solution to a final volume of 60 mL. ,

strength becomes 1/6 times .

So the first two experiment gives three solution  each one-half as concentrated as the previous .

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Answer:

0.241  × 10³⁰ molecules

Explanation:

Given data:

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Solution:

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The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

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For 0.04× 10⁷  moles of Cr(HCO₃)₃:

0.04× 10⁷  moles × 6.022 × 10²³ molecules / 1 mol

0.241  × 10³⁰ molecules

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