The work done by the gas when the gas expands will be 567.65 ft-lb.
<h3>What is the work done for an isothermal process?</h3>
The Pressure is inversely proportional to the volume.
Let the initial pressure and initial volume be P₁ and V₁, and the final volume be V₂.
Then the work done by the gas will be
WD = P₁ V₁ ln (V₂ / V₁)
A quantity of the gas with an initial volume of 2 cubic feet and an initial pressure of 700 pounds per square foot.
The gas expands to a volume of 3 cubic feet.
Then the work done by the gas will be
WD = 700 x 2 x ln (3/2)
WD = 1400 x 0.405
WD = 567.65 ft-lb
The work done by the gas when the gas expands will be 567.65 ft-lb.
More about the work done for isothermal process link is given below.
brainly.com/question/4218306
#SPJ1
Answer:
Options A, B and C are CORRECT PROPORTIONS
Step-by-step explanation:
Option A
3:5 = 6:10
The LHS must equal the RHS
3:5 is in it's lowest term.
6/10 will be in it's lowest term by dividing the numerator and denominator by 2.
6/10 = 3/5
Option B
3/6 and 5/10.
Diving 3/6 fractions by 3
= 1/2
Dividing 5/10 fraction by 5
= 1/2
Option C
Dividing 6/3 by 3 = 2
Dividing 10/5 by 5 = 2
Thats how you work through equivalent proportional fractions
Answer:
Here, the coordinates of the given rectangle are (1,2), (3,2), (1,-1) and (3,-1)
In the dilation by the scale factor k with centered at origin,
Thus, If the dilation occurs by the scale factor of 2 with centered at origin,
New coordinates of the Rectangle are,
Thus, the coordinates of new rectangle are,
(2,4), (6,4), (2,-2) and (6,-2)
