B = 3h . . . . . . . .given by the problem statement
A = (1/2)bh . . . . formula for the area of a triangle
486 cm² = (1/2)*(3h)*h . . . substitute given information
(2/3)*486 cm² = h² . . . . . .multiply by 2/3
√324 cm = h . . . . . . . . . . . . . .take the square root
The height is 18 cm.
The base is 3*18 = 54 cm.
If x=students, the equation would be x=12 (x is less than of equal to twelve). I don’t know what you mean by constraints; perhaps if you explain more, I could help?
Answer:
Step-by-step explanation:
6c+31=4c+13
6c - 4c = 13 - 31
2c = -18
c = -9.
The length of the radius would sqrt(1+4), or sqrt(5).
2
The angle would be in Quadrant II and would be arctan ------ , or arctan (-2).
-1
Find this angle using a calculator or table.
Then you end up with -1+2i = sqrt(5) angle arctan(-2). The angle would be + and measured from the + horizontal axis.
