ANSWER
45.6cm to the nearest tenth.
EXPLANATION
The diagonal of the rectangular painting is 62cm.
The height of the painting is 42 cm.
The height of the painting h , the diagonal, and the width of the painting forms a right triangle with the diagonal being the hypotenuse.
From the Pythagoras Theorem,
The width of the painting is 45.6cm to the nearest tenth.
Answer:
x^2/400 + x^2/625
(x-0)^2/400) +(y-0^2/625)
x^2=400
X=sqrt. 400
x = 20
y^2=625
y = sqrt. 625
y= 25
a^2-c^2=b^2
sqrt 400-625 = c
20-25=c
The correct answer is c=-5
(-5,0)
(5,0)
Step-by-step explanation:
Marie has a small copy of Rene margrittes famous painting. The Schoolmasters. Her copy has dimensions of 2 inches by 1.5 inches. The scale of her copy is 1 inch:40 cm What is the dimensions of the original painting?
Every 1 inch on her copy is the same as 40 cm on the original.
You just have to multiply by 40 and convert to centimetres.
2 x 40 = 80
1.5 x 40 = 60
So the original painting is:
80cm by 60cm
First you do the exponents so 10^-3 is:
1/10^3 (change it so it is not a negative exponent, so make it its reciprocal)
1/(10*10*10) = 1/1000 = 0.001
A reasonable estimate would be 180 students with blue eyes
