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PIT_PIT [208]
3 years ago
7

The equation y=x^2-12x+45 models the number of books y sold in a bookstore x days after an award-winning author appeared at an a

utograph-signing reception. What was the first day that at least 100 copies of the book were sold?
Mathematics
1 answer:
romanna [79]3 years ago
7 0
Answer: The first day the author reaches 100 days is on day 16.

To solve this problem, you could use a graphing calculator to graph the given equation. Then, determine when this line crosses 100. It crosses when x = 15.539. Therefore, we would have to round up to 16 so it is at least 100.

You could use the quadratic equation to solve: 100 = x^2 -12x + 45

Either you will get 16. If you use the quadratic formula, make sure to only use the positive answer.
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A room has eight switches, each of which controls a different light. Initially, exactly five of the lights are on. Three people
aivan3 [116]

Answer:

The probability that 3 lights are on after the third person exited the room is 39/128

Step-by-step explanation:

In order for 6 switches to be on at the end, we need exactly 2 people turning on a switch and the other one turning one off. There are 3 possibilities:

  • The first two persons turn the switch in and the last one turns it off
  • The first and last person turn the switch in and the middle one tunrns it off
  • The first person turns the switch off and the 2 remaining turn the switch in

Note that after turning off one switch one more switch will be available to be switched in and one less will be available to be switch off. The contrary happens when someone turns in a switch.

Lets calculate the probability for the first scenario. The probability for the first person to turn the switch in is 3/8, because there are 3 lights off. For the second person, there will be only 2 lights off, thus, the probability for him or her to turn the switch in is only 2/8, leaving only 1 light off and 7 on. The third person will have, as a consecuence, a probability of 7/8 to turn off one of the 7 switches. This gives us a probability of 3/8 * 2/8 * 7/8 = 21/256 for the first scenario.

For the second scenario we will have a probability of 3/8 for the first person, a probability of 6/8 for the second one (he has to turn a switch off this time), and a probability, again, of 3/8 for the third one, giving us a probability of 3/8*6/8*3/8 = 27/256 for the second scenario.

For the third scenario, the first person has to turn off the switch, and it has a probability of 5/8 of doing so. The second person will have 4 switches to turn on, so it has a probability of 4/8 = 1/2, and the third person will have one switch less, thus, a probability of 3/8 of turning a switch on. Therefore, the probability of the third scenario is 5/8*1/2*3/8 = 15/128 = 30/256

By summing all the three disjoint scenarios, the probability that six lights are on is 21/256+27/256+30/256 = 78/256 = 39/128.

8 0
3 years ago
Combine like terms to write a simplified expression: <br><br> 12p + 11 - 5p + 3
liubo4ka [24]

Answer:

7p + 14

Step-by-step explanation:

add 12p and -5p to get 7p

then add 11 and 3 to get 14

your equation will be 7p + 14

7 0
2 years ago
Read 2 more answers
What’s the measure of str
IrinaVladis [17]

Answer:

I believe its 45 degrees.

5 0
3 years ago
Find the set of outcomes that occur when we flip 3 coins and obtain at least two tails.
Vikentia [17]
First, I would show all the outcomes possible. To determine the number of the total outcomes, you use the formula: rⁿ, where r is the number of outcomes in 1 flip, and n is the number of lips. Thus, 2³ = 8 outcomes. These outcomes are:

1. HHH
2. TTT
3. HHT
<em>4. HTT</em>
5. HTH
6. THH
<em>7. TTH</em>
<em>8. THT</em>

From the given outcomes, there are <em>3 outcomes</em> that has at least two tails. These are the ones in bold characters.
5 0
3 years ago
Mrs. chin paid a 20 percent tip on the bill for lunch.if the tip amount was $2.75, what was the bill for lunch before the tip wa
bija089 [108]
The original bill for the lunch was $13.75
8 0
3 years ago
Read 2 more answers
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