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arlik [135]
3 years ago
5

What is a cubic polynomial function in standard form with zeros 1,1,and -3?

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
8 0

Answer:

f(x) = x³ + x² - 5x + 3

Step-by-step explanation:

The cubic polynomial has zeros at 1, 1, - 3.

Therefore, x = 1, 1, - 3 are the roots of the polynomial and hence, (x - 1), (x - 1) and (x + 3) will be factors of the cubic polynomial.

Hence, we can write the polynomial as a function of x as

f(x) = (x - 1)(x - 1)(x + 3)

⇒ f(x) = (x² - 2x + 1)(x + 3)

⇒ f(x) = x³ - 2x² + 3x² + x - 6x + 3

⇒ f(x) = x³ + x² - 5x + 3

So, this is the cubic polynomial function in standard form. (Answer)

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Answer:

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Step-by-step explanation:

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And we know that,

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Considering case (2):

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Here, it is possible for P(W) and P(E) to get multiply values.

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Considering cases (1) & (2):

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but for P(E) = 0.2 (5 even balls) ⇒ P(W∨E) = 0.6

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