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3 years ago

3. Fill in the blanks with center, circle, directrix, focus, line, parabola, or radius.

2 answers:

6 0

A ___line___ is the set of all points that are equidistant from two points.

A ___circle___ is the set of all points that are equidistant from a given point. The given point is called the ____center____. The segment showing the distance is called the ____radius____.

A ___parabola____ is the set of all points equidistant from a single point and a single line. The single point is called the ____focus____ and the single line is called the ____directix_____.

julsineya [31]3 years ago

6 0

Answer and Step-by-step explanation:

A line is the set of all points that are equidistant from two points.

Because line is the set of line which two points and it can be extended from both the sides.

So, there are no end points.

A Circle is the set of all points that are equidistant from a given point. The given point is called the centre . The segment showing the distance is called the radius.

Circle is the set of points equidistant from the centre and distance between centre and any point on circumference of circle is known as radius.

A parabola is the set of all points equidistant from a single point and a single line. The single point is called the focus and the single line is called the directrix.

Parabola is equidistant from focus and directrix.

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Answer: $3.87

Step-by-step explanation:

3.10 increase 24.8% =

3.10 × (1 + 24.8%) = 3.10 × (1 + 0.248) = 3.8688

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What is the correct solution set for the following graph? graph showing two lines, labeled a and b, one atop the other

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Given:

Line a and line b

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Which is the correct solution set for the graph.

Solution:

Here line a is on the line b.

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3 years ago

1. A flower shop wishes to add the valuable Waimea orchid to its product list. They purchase a large shipment of bulbs from a su

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Answer:

The concern of the florist that these bulbs are not Waimea orchids, but a similar appearing hybrid maybe true.

Step-by-step explanation:

A Chi-square goodness of fit test can be used to perform the hypothesis test.

The hypothesis is defined as:

<em>H</em>₀: There is no difference between the observed and expected value.

<em>Hₐ</em>: There is a difference between the observed and expected value.

The test statistic is:

$\chi^{2}=\sum \frac{(O-E)^{2}}{E}$

The total number of Waimea orchid bulbs is, 60.

7x + 5x + 4x + 4x = 60

20x = 60

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The expected number of Waimea orchid bulbs are:

Blue = 7 × 3 = 21

Red = 5 × 3 = 15

Violet = 4 × 3 = 12

Orange = 4 × 3 = 12

Consider the table provided.

The test statistic value is:

$\chi^{2}=\sum \frac{(O-E)^{2}}{E}=14.981$

The decision rule:

The null hypothesis will be rejected if $\chi^{2}\geq \chi^{2}_{\alpha, (k-1)}$ .

Compute the critical value as follows:

$\chi^{2}_{0.05, (4-1)}= \chi^{2}_{0.05, (3)}=7.815$

The test statistic value is 14.981.

$\chi^{2}=14.981> \chi^{2}_{\alpha, (k-1)}=7.815$

The null hypothesis will be rejected at 5% level of significance.

Conclusion:

As the null hypothesis was rejected it implies that there is a significant difference between the observed and expected value.

Thus, the concern of the florist that these bulbs are not Waimea orchids, but a similar appearing hybrid maybe true.

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