The answer is False!
P - dominant allele for inflated pods
p - recessive allele for inflated pods
PP - homozygote with inflated pods
Pp - heterozygote with inflated pods
pp - homozygote with inflated pods
S - dominant allele for round seeds
s - recessive allele for wrinkled seeds
SS - homozygote with round seeds
Ss - heterozygote with round seeds
ss - homozygote with wrinkled seeds
1. <span>A Pea plant that is homozygous for inflated pods are heterozygous for round seeds: PPSs
2. A</span><span> plant that is heterozygous for inflated pods and a homozygous for wrinkled seeds: Ppss
Let's look at their genotypes separately, and cross them that way:
Parents: PP x Pp
Offspring: PP PP Pp Pp
All of the offspring will have the same phenotype (100% = 1). So, this trait does not affect phenotypic ratio
</span>Parents: Ss x ss
Offspring: Ss Ss ss ss
Half of the offspring will have wrinkled seeds and half of them will have round seeds: 50% : 50% = 1 : 1
So, the phenotypic ratio is not 1 : 3
Organisms adapt to changes in their surroundings.
Answer:
The correct answer is option E.
Explanation:
Voluntary hyperventilation results in alkalosis, not in acidosis. Alkalosis takes place when the body possesses too many bases. It can take place due to decreased levels of carbon dioxide or due to enhanced level of bicarbonates in the blood, that is, a base.
Emphysema directly impairs exhalation more than it directly impairs inhalation. Emphysema refers to a lung disorder, which leads to shortness of breath. In the individuals suffering from the condition, the air sacs in the lungs, that is, alveoli get damaged.
The hemoglobin-oxygen dissociation curve shifts to the right at the time of metabolic acidosis. The low partial pressure of oxygen within the lungs results in the constriction of pulmonary arterioles. Thus, all the mentioned statements are false.
dominant trait is opposed to a recessive trait which is expressed only when two copies of the gene are present.
