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3 years ago

What is 200 +90 + 3 in standard form?

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

4 0

Answer: 293

200 = 2

90 = 9

3 = 3

Answer is 293.

Hope this helps!

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Please solve!!! Bbkakakaj

sdas [7]

Answer:

B is the answer because yes

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2 years ago

ILL GIVE BRAINLIST ON WHOEVER GETS RIGHT!!!!!!!

Korvikt [17]

Answer:

hey,its option a

Step-by-step explanation:

because angle F= angle M and angle G= angle L

and angle H= angle N

To know third angle in ∆HGF

,we know sum of all angles in a triangle is 180°

______________________________

let angle H be unknown value x

x+51+36=180

x=180-87 ---------------- 1

similarly in ∆MNL

let angle be y

51+36+y=180

y=180-87----------------2

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From 1&2 we observe qngle x= angle y

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3 0

3 years ago

I need this solved please

ss7ja [257]

Answer:

x = 23

y = 128

Step-by-step explanation:

Theorem:

The measure of an exterior angle of a triangle is equal to the sum of the measures of its remote interior angles.

98 = 2x + 3x - 17

115 = 5x

x = 23

Angles 3x - 17 and y form a linear pair, so they are supplementary.

3x - 17 + y = 180

3(23) - 17 + y = 180

69 - 17 + y = 180

52 + y = 180

y = 128

7 0

2 years ago

Read 2 more answers

The formula for the surface area of a cylinder is s

lyudmila [28]

Answer:

It is 2πrh + 2π $r^{2}$

Step-by-step explanation:

8 0

3 years ago

Find the roots of:

Elena-2011 [213]

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \ 2x^3-7x^2+8x-3=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:

| 2 -7 8 -3

1 | 2 -5 3

| 2 -5 3 0

1 | 2 -3

2 -3 0

So the factorization is (x-1)² (2x-3)=0. So:

$\bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2} }$

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \ x^3-x^2-4=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:

| 1 -1 0 -4

2 | 2 2

1 2 2 0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

$\bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }$

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \ 6x^3+7x^2-9x+2=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:

| 6 7 9 2

-2 | -12 10 -2

6 -5 1 0

So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

$\bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}$

$\large\displaystyle\text{$\begin{gathered}\sf \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}$

6 0

2 years ago