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DaniilM [7]
3 years ago
12

The hypotenuse of a 45-45-90 triangle has a length of 10 units. what is the length of one of its legs?

Mathematics
1 answer:
Blizzard [7]3 years ago
4 0

the length of a leg on a 45-45-90 triangle given the hypotenuse is half the length of the hypotenuse times sqrt(2)

hypotenuse = 10

 10/2 =5

 so the answer should be 5sqrt(2), which I don't see as a choice

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Let g(x)=2x and h(x)=x^2+4 find the value. (hog)(a)
lisov135 [29]
In short, (h o g)(a) is just h(    g(a)    ).

so what we can do is simply get g(a) first and then plug that in h(x).

\bf \begin{cases}
g(x)&=2x\\
h(x)&=x^2+4\\
(h\circ g)(a)&=h(~~g(a)~~)
\end{cases}
\\\\\\
g(a)=2(a)\implies g(a)=2a
\\\\\\
h(~~g(a)~~)\implies h(~~2a~~)=(2a)^2+4
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h(~~2a~~)=(2^2a^2)+4\implies  h(~~2a~~)=4a^2+4
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3 years ago
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Anna007 [38]

Answer:

Use pythagoreum theorem to determine whether it is or isn't since I'm not really sure myself but here's my calculations.

Step-by-step explanation:

We need to find AC.

Picture a triangle called ABC. AB is one side and BC the other while AC is the hypotenuse.

AC=

ac =  \sqrt{ab ^{2}  +  {bc}^{2} } \\ ac = \sqrt{ {7}^{2} }  +  {3}^{2}  \\ ac =  \sqrt{49 + 9}  \\ ac =  \sqrt{58 }  \\ ac = 7.6

Round up the 7.6 to a whole number and you get AC=8. To get perimeter of a triangle simply add the sides together to get 18.

Not really sure about my answer but hope this helped.

5 0
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notka56 [123]
A= (1/2) b*h
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