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3 years ago

43-44 please and thanks

Mathematics

1 answer:

KatRina [158]3 years ago

4 0

The easiest way to do the fractions is is you turn them to decimals.

43. >
44. >

You think it might be the othe way around, but it’s a negative. So if it’s -36 and -35, the -35 will be bigger. Think about the number line. -36 comes before -35.

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Which coordinate could represent the amount of granola when selling at a unit rate of R pounds per dollar?

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1 year ago

Which of the following ordered pairs are solutions to the equation y=−2x+6? (Select all that apply.) Select all that apply: (0,6

yuradex [85]

Answer:

(0,6)

(1,4)

Step-by-step explanation:

(0,6)

1. Plug in 0 for x and solve to see if 6 results for y

y = -2(0) + 6

0 + 6 = 6

y = 6

When 0 is plugged in for x, y equals 6 which makes (0,6) a solution.

(1,4)

1. Plug in 1 for x and solve to see if 4 results for y

y = -2(1) + 6

-2 + 6 = 4

y = 4

When 1 is plugged in for x, y equals 4 which makes (1,4) a solution.

(-2,-2)

1. Plug in -2 for x and solve to see if -2 results for y

y = -2(-2) + 6

4 + 6 = 10

10 ≠ -2

When -2 is plugged in for x, y does not equal -2 which means (-2,-2) is not a solution.

5 0

3 years ago

Automobile policies are separated into two groups: low-risk and high-risk. Actuary Rahul examines low-risk policies, connuing un

jonny [76]

Answer:

The probability that Actuary Rahul examines fewer policies that Actuary Toby = 0.2857

Step-by-step explanation:

It is said that Actuary Rahul examines a low risk policy

Probability of a low risk policy having a claim = 10% = 0.1

Actuary Toby examines high risk policy

Probability of a high risk policy having a claim = 20% = 0.2

Let the number of policies examined by actuary Rahul before he finds a claim and stop be n

Probability that actuary Rahul examines exactly n policies = $0.9^{n-1} (0.1)$

Probability that Toby examines more than n policies = $0.8^n$

Since the claim statuses of policies are mutually independent, the probability that both events happen simultaneously = $0.9^{n-1} (0.1) (0.8)^n$

probability that both events happen simultaneously = $\frac{0.1}{0.9} (0.72^{n})$

The probability that Actuary Rahul examines fewer policies that Actuary Toby = $\sum\limits^ \infty_1 {\frac{0.1}{0.9} 0.72^{n} }$ = $\frac{1}{9}\sum\limits^ \infty_1 { 0.72^{n} } = \frac{1}{9} (\frac{0.72}{1-0.72} ) = \frac{1}{9} (\frac{0.72}{0.28} )$

The probability that Actuary Rahul examines fewer policies that Actuary Toby = 0.2857

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3 years ago

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