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enot [183]
3 years ago
15

Simplify an expression

Mathematics
1 answer:
fiasKO [112]3 years ago
5 0
Is there a question that goes with this command?

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The circumference of the circle is about 25.12 inches. Hope it help!
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Answer number one asap this is not a joke so please not random cmts thx will report if u do!
STALIN [3.7K]
1. The area of one face of the bar is
.. face area = (50 mm)*(90 mm) = 4500 mm^2
The area of two sides of the bar is
.. side area = (50 mm +90 mm)*(3.5 mm) = 490 mm^2

Together, those areas cover half the bar, so the total paper required is
.. 2*(4500 mm^2 +490 mm^2) = 9980 mm^2 . . . . . . 3rd selection

2. The length of the central rectangle is
.. 8 ft + 6 ft + 10 ft = 24 ft
Its width is 7 ft, so its area is
.. Arect = (7 ft)*(24 ft) = 168 ft^2

Each of the two triangles has a base of 8 ft and a height of 6 ft, so together, they have an area of
.. Atriangles = (8 ft)*(6 ft) = 48 ft^2

Then the total area of the prism is
.. Atotal = Arect +Atriangles
.. = (168 ft^2) +(48 ft^2)
.. = 216 ft^2
8 0
3 years ago
How many 1/2 foot pieces can be cut from 6 foot ribbon?
MatroZZZ [7]
Number of ribbons that can be cut = 6 ÷ 1/2 
Number of ribbons that can be cut = 6 x 2/1
Number of ribbons that can be cut = 12 

 -----------------------------------------------------------------------------------------
Answer: 12  1/2 foot pieces can be cut from 6 feet ribbon
 -----------------------------------------------------------------------------------------

8 0
3 years ago
2.
iren [92.7K]

Answer:

  • Part A: The price of fuel A is decreasing by 12% per month.

  • Part B: Fuel A recorded a greater percentage change in price over the previous month.

Explanation:

<u>Part A:</u>

The function     f(x)=2.27(0.88)^x     calculates the price of fuel A each month by multiplying the price of the month before by 0.88.

Month       price, f(x)

1                 2.27 (0.88) = 1.9976 ≈ 2.00

2                2.27(0.88)² = 1.59808 ≈ 1.60

3                2.27(0.88)³ = 1.46063 ≈ 1.46

Then, the price of fuel A is decreasing.

The percentage per month is (1 - 0.88) × 100 = 12%, i.e. the price decreasing by 12% per month.

<u>Part B.</u>

<u>Table:</u>

m       price, g(m)

1          3.44

2         3.30

3          3.17

4         3.04

To find if the function decreases with a constant ration divide each pair con consecutive prices:

  • ratio = 3.30 / 3. 44 = 0.959 ≈ 0.96
  • ratio = 3.17 / 3.30 = 0.960 ≈ 0.96
  • ratio = 3.04 / 3.17 = 0.959 ≈ 0.96

Thus, the price of fuel B is decreasing by (1 - 0.96) × 100 =4%.

Hence, the fuel A recorded a greater percentage change in price over the previous month.

5 0
3 years ago
A website manager has noticed that during the evening​ hours, about 5 people per minute check out from their shopping cart and m
Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is​ made

c) 0.05% probability that seven people make a purchase in the next four ​minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that \mu = 5

a) What model might you suggest to model the number of purchases per​ minute? ​

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per​ minute.

b) What is the probability that in any one minute at least one purchase is​ made? ​

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

P(X = 0) + P(X \geq 1) = 1

We want to find P(X \geq 1)

So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067

1 - 0.0067 = 0.9933.

99.33% probability that in any one minute at least one purchase is​ made

c) What is the probability that seven people make a purchase in the next four ​minutes?

The mean is 5 purchases in a minute. So, for 4 minutes

\mu = 4*5 = 20

We have to find P(X = 7).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-20}*(20)^{7}}{(7)!} = 0.0005

0.05% probability that seven people make a purchase in the next four ​minutes

8 0
3 years ago
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