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Sever21 [200]
3 years ago
7

In how many ways can 8 children be seats in a row

Mathematics
2 answers:
Levart [38]3 years ago
7 0
I think it's 40,320 which is 8 factorial since the first child has 8 options 2nd child has 7 options, etc
Leya [2.2K]3 years ago
4 0
Its 7 ways they all can be seated
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Step-by-step explanation:

We assume that the edge of the small square is x (inches).

As the edge of the larger square is 2 inches greater than that of the smaller one, so that the edge of the larger square = edge of the small square  + 2 = x + 2 (inches)

The equation to calculate the are of a square is: <em>Area = Edge^2 </em>

So that:

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+) The area of the smaller square is: <em>Area small square = </em>x^{2}<em>(square inches)</em>

<em />

As difference in area of both squares are 64 square inches, so that we have:

<em>Area large square - Area small square  = 64 (square inches)</em>

<em>=> </em>(x+2)^{2} -x^{2} =64<em />

<em>=>  </em>x^{2}+4x+4  -x^{2} =64<em />

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