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iVinArrow [24]
3 years ago
13

(07.04 MC)

Mathematics
1 answer:
KIM [24]3 years ago
4 0
Answer: 4.00

Explanation

To find the maximum value for x, the hypotenuse, with a given of an angle 30° and a height of 2 m, we can see that 30° is directly opposite the side of 2 m, in which case we may use the sin of 30° to find the hypotenuse.

Remember that the sin = opposite/hypotenuse, so sin30° = 2/x

1) sin30 = 2/x
2) 1/2 = 2/x
3) x = 4

Hope this helps :)
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To solve divide both sides by 4 to cancel out the 4 on the x side to get x alone. Then just do -10/4. That gives you 2.5 so (X=2.5). Hope I helped and have a great day and night

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Marika is training for a track race She starts by sprinting 100 yards . She gradually increases her distance , adding 4 yards a
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For this case, you must use the given expression, taking into account that:
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Write the given second order equation as its equivalent system of first order equations. u′′−5u′−4u=1.5sin(3t),u(1)=1,u′(1)=2.5
lakkis [162]

Answer:

hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to

Answer:  v = 5v + 4u + 1.5sin(3t),

  • 0
  • 1
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  • 5
  • 0
  • 1.5sin(3t)
  • 1
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Step-by-step explanation:

u" - 5u' - 4u = 1.5sin(3t)        where u'(1) = 2.5   u(1) = 1

v represents the "velocity function"   i.e   v = u'(t)

As v = u'(t)

<em>u' = v</em>

since <em>u' = v </em>

v' = u"

v'  = 5u' + 4u + 1.5sin(3t)   ( given that u" - 5u' - 4u = 1.5sin(3t) )

    = 5v + 4u + 1.5sin(3t)  ( noting that v = u' )

so v' = 5v + 4u + 1.5sin(3t)

d/dt \left[\begin{array}{ccc}u&\\v&\\\end{array}\right]= \left[\begin{array}{ccc}0&1&\\4&5&\\\end{array}\right]  \left[\begin{array}{ccc}u&\\v&\\\end{array}\right] + \left[\begin{array}{ccc}0&\\1.5sin(3t)&\\\end{array}\right]

Given that u(1) = 1 and u'(1) = 2.5

since v = u'

v(1) = 2.5

note: the initial value for the vector valued function is given as

\left[\begin{array}{ccc}u(1)&\\v(1)\\\end{array}\right]  = \left[\begin{array}{ccc}1\\2.5\\\end{array}\right]

7 0
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