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2 years ago

12

Need help ASAP please fellas!

2 answers:

labwork [276]2 years ago

7 0

Use BEMDAS:
Brackets, Exponents, Multiplication and Division, Addition and Subtraction
$1.2+0.8:4-3\cdot(0.7-0.81)=1.2+0.2-3\cdot(-0.11)=1.2+0.2+0.33=1.73$

gladu [14]2 years ago

6 0

The answer to this question is 1.73
                                         1.2 + 0.8 ÷ 4 - 3(0.7 - 0.81)
                                       = 1.2 + 0.8 ÷ 4 - 3(-0.11)
                                       = 1.2 + 0.2 - 3(-0.11)
                                       = 1.2 + 0.2 + 0.33
                                       = 1.73

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vova2212 [387]

Answer:

Step-by-step explanation:

From table 1,

f(x) = bˣ

For x = -1,

f(-1) = 0.5

0.5 = (b)⁻¹

b = $\frac{1}{0.5}$

b = 2

For x = 1.585,

f(1.585) = 3

3 = $2^{1.585}$

3 = $2^{1}\times2^{0.585}$

$2^{0.585}=\frac{3}{2}$

$2^{0.585}=1.5$

For x = 2.585,

f(2.585) = $2^{2.585}$

= $2^{2}\times 2^{0.585}$

= 4 × 1.5 [Since, $2^{0.585}=1.5$ ]

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From table 2,

g(x) = $\text{log}_b(x)$

For x = 0.5,

g(0.5) = -1

-1 = $\text{log}_b(0.5)$

b⁻¹ = 0.5

b = 2

For x = 2,

g(2) = 1

1 = $\text{log}_2(2)$

For x = 6,

g(6) = 2.585

2.585 = $\text{log}_2(6)$

2.585 = $\text{log}_2(2\times 3)$

2.585 = $\text{log}_2(2)+\text{log}_2(3)$

2.858 - 1 = $\text{log}_2(3)$

$\text{log}_2(3)=1.585$

For x = 3,

g(3) = $\text{log}_2(3)$

g(3) = 1.585

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