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3 years ago

6

Henry and Jose are gaining weight for football. Henry weighs 205 pounds and is gaining 2 pounds per week. Jose weighs 195 pounds

and is gaining 3 pounds per week. When will they weigh the same?

1 answer:

Digiron [165]3 years ago

6 0

Answer:

they will both weigh the same at week 10

Step-by-step explanation:

both will weigh 225 at week 10

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If T(x, y) = (x + 5, y + 6) and Pris the image of P, what is the rule for the translation in which P is the image of P'? T(x, y)

xxTIMURxx [149]

Answer:

The translation is;

$T(x,y)=(x-5,y-6)$

Explanation:

Given the translation rule;

$T(x,y)=(x+5,y+6)$

when P' is the image of P.

For the inverse, when P is the image of P', the Translation rule would become;

$\begin{gathered} x=x^{\prime}+5 \\ x^{\prime}=x-5 \\ y=y^{\prime}+6 \\ y^{\prime}=y-6 \\ So,\text{ the translation rule becomes;} \\ T(x,y)=(x-5,y-6) \end{gathered}$

The translation is;

$T(x,y)=(x-5,y-6)$

3 0

1 year ago

The expression 3/4×1/2 represents a fraction of a circle that is shaded. Which diagram shows the correct shading?

sergiy2304 [10]

Hello,

Here is your answer:

The proper answer to this question is option D.

Here is how:

First solve the equation:

3*1=3
4*2=8

Which means your answer is D.

If you need anymore help feel free to ask me!

Hope this helps!

4 0

3 years ago

Read 2 more answers

The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

∴ we get

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

8 0

3 years ago

I don’t have a problem with

WARRIOR [948]

Answer:

9

Step-by-step explanation:

27 - 18 = 9

5 0

3 years ago

Question 2 of 10<br> What is the surface area of the rectangular pyramid below?

Ymorist [56]

Answer:

363

Step-by-step explanation:

11x11=121

((11x11)÷2)x4=11x11x2=121x2=242

121+242=363

5 0

2 years ago