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cluponka [151]
3 years ago
10

Use the confidence level and Sample data to find the margin of error E. Round your answer to the same number of decimal places a

s the sample mean unless otherwise noted.
College students annual earnings: 99% confidence; n=76, x=$3016, standard deviaton=$872

A)$233

B)$891

C)$258

D)$196
Mathematics
1 answer:
lakkis [162]3 years ago
8 0

Answer:

C)$258

Step-by-step explanation:

Margin of error = critical value × standard error

ME = CV × SE

n > 30, so we can approximate CV with a normal distribution.  At P = 99%, CV = 2.576.

SE = σ / √n

SE = 872 / √76

SE = 100

So the margin of error is:

ME = 2.576 × 100

ME = 258

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