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3 years ago

Find the equation of the circle whose center and radius are given. Center:(-2,-5) Radius=1

Mathematics

1 answer:

maxonik [38]3 years ago

8 0

Answer:

( x+2)^2 + (y+5)^2 = 1

Step-by-step explanation:

The equation of a circle can be written in the form

( x-h)^2 + (y-k)^2 = r^2

where ( h,k) is the center and r is the radius

( x- -2)^2 + (y- -5)^2 = 1^2

( x+2)^2 + (y+5)^2 = 1

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35.6 = the square root of 15.3^2 + the square root of x^2. Find x.

vivado [14]

Answer:

x = 50.9

Step-by-step explanation:

35.6 = √(15.3²) + √(x²)

35.6 = 15.3 + x

x = 35.6 + 15.3

x = 50.9

5 0

3 years ago

7. Which of these polynomial functions gives the number of lights in a hexagonal rig (six sides) with n rows? (Hint: Look for a

morpeh [17]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Below are the answers:

7. C. H(n) = ½n^2 + n + 1
8. D. As the number of rows increases, the hexagonal rig gets closer to having twice as many lights as the square rig.

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3 years ago

The mean MCAT score 29.5. Suppose that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.

Paul [167]

Answer:

We conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

Step-by-step explanation:

We are given that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.2 with a standard deviation of 4.2.

Let $\mu$ = population mean score

So, Null Hypothesis, $H_0$ : $\mu \leq$ 29.5 {means that the students that took the Kaplan tutoring have a mean score less than or equal to 29.5}

Alternate Hypothesis, $H_A$ : $\mu$ > 29.5 {means that the students that took the Kaplan tutoring have a mean score greater than 29.5}

The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean MCAT score = 32.2

s = sample standard deviation = 4.2

n = sample of students = 40

So, the test statistics = $\frac{32.2-29.5}{\frac{4.2}{\sqrt{40} } }$ ~ $t_3_9$

= 4.066

The value of t-test statistics is 4.066.

Now, at 0.05 level of significance, the t table gives a critical value of 1.685 at 39 degrees of freedom for the right-tailed test.

Since the value of our test statistics is more than the critical value of t as 4.066 > 1.685, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

3 0

3 years ago

Round 67,436,828,104 to the nearest million

S_A_V [24]

It would be 67,437,000,000 since the eight in 67,436,(8)28,104 rounds the 6 up to a 7.

4 0

3 years ago

Read 2 more answers

How do you write 56% as a fraction in simplest form?

Alecsey [184]

56% can be represented with 56/100. That fraction can be reduced (or simplified) to 14/25.

3 0

3 years ago