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yuradex [85]
3 years ago
8

Please help me answer this with an explanation

Mathematics
2 answers:
Nata [24]3 years ago
5 0
You need to find the slope first. (-9,-4). (3,4)

-4-4= -8
-9-3 =-12. Slope is -8/-12 or 8/12 or 2/3


Perpendicular is the negative reciprocal. Or flip over the 2/3 and make it negative.

The answer is - 3/2
elixir [45]3 years ago
5 0

The change in y as we move from the first point to the second is 8, and the corresponding change in x is 12.  Thus, the slope of the line thru these two points is 8/12, or 2/3 (answer C).

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Solve the following 5/7÷25/27
Licemer1 [7]
The answer is 27/35 :)
8 0
3 years ago
A sample of carbon dioxide occupies a volume of 3.50 l at 125 kpa pressure. what pressure would the gas exert if the volume was
Novosadov [1.4K]

The gas exerts a pressure of 218.75 kPa when its volume is reduced to 2.0 L, following the behavior of an ideal gas.

Ideal gas behavior:

Suppose the initial volume of carbon dioxide gas is V = 3.5l

Initial pressure is P = 125 kPa

Since the volume is reduced to 2.0l, the final volume is shown as V'= Will be done. 2L

The final pressure of the gas is P'.

We consider the behavior of gas to be ideal. From the ideal gas equation, it becomes as follows.

PV = P'V'

125 × 3.5 = P'× 2

P'= 218.75 kPa

Therefore, the final pressure is 218.5 kPa.

Learn more about ideal gas, visit brainly.com/question/11676583?referrer=searchResults

#SPJ4

3 0
2 years ago
What is 3/5 ÷ 1/2? please help
Fynjy0 [20]
3/5 ÷ 1/2 step 1: keep change flip Step 2: 3/5×2/1 step 3: solve 3/5 ×2/1= 6/5 in the simplified form it is 1 1/5
4 0
3 years ago
a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the
kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Step-by-step explanation:

The population growth can be modeled as an exponential function,

P(t) = P_0e^{rt}

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

P(t) = 45e^{0.22t}

Assuming that the starting year is 2020,

Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0
3 years ago
What is 10/12 as a decimal ?
ZanzabumX [31]
<span>0.833333333333333 is the answer</span>
5 0
3 years ago
Read 2 more answers
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