1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nutka1998 [239]
3 years ago
15

X(21)+x(4)=300 I need solving

Mathematics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

12

Step-by-step explanation:

21x + 4x = 300         Put brackets around the first two terms.

(21x + 4x) = 300        Pull the x outside the brackets. Use the distributive property.  Combine the left

25x = 300                 Divide by 25

25x/25=300/25        Do the division

x = 12

                 

You might be interested in
Juan wishes to build a garden at the bottom of his property. He wants to split it in two, like the diagram below, so he can plan
SCORPION-xisa [38]

Answer:

20 ft by 60 ft

Step-by-step explanation:

"What should the dimensions of the garden be to maximize this area?"

If y is the length of the garden, parallel to the stream, and x is the width of the garden, then the amount of fencing is:

120 = 3x + y

And the area is:

A = xy

Use substitution:

A = x (120 − 3x)

A = -3x² + 120x

This is a downward facing parabola.  The maximum is at the vertex, which we can find using x = -b/(2a).

x = -120 / (2 · -3)

x = 20

When x = 20, y = 60.  So the garden should be 20 ft by 60 ft.

4 0
3 years ago
Metric unit of length
Zarrin [17]
Centimeters are the metric unit of length
6 0
3 years ago
Read 2 more answers
(a) Suppose you have 9 gold coins that look identical, but you also know one (and only one) of them is counterfeit. The counterf
alisha [4.7K]

Answer:

Step-by-step explanation:

You can split the coins into 3 groups, each of them has 3 coins. Weigh group 1 vs group 2, if one is lighter, that group has the fake coin. If both groups weigh the same, then group 3 has the fake coin.

Continue to split the group that has the fake coin into 3 groups, each group has 1 coin. Now apply the same procedure and we can identify the fake coin.

Total of scale usage is 2

b) if you have 3^n coins then you can apply the same approach and find the fake coin with just n steps. By splitting up to 3 groups each step, after each step you should be able to narrow down your suspected coin by 3 times.

Step 1: you narrow down to group of \frac{3^n}{3} = 3^{n-1} coins

Step 2: you narrow down to group of \frac{3^{n-1}}{3} = 3^{n-2} coins

Step 3: you narrow down to group of \frac{3^{n-2}}{3} = 3^{n-3} coins

...

Step n: Step 1: you narrow down to group of 3^{n-n} = 3^0 = 1coin

8 0
3 years ago
There is a bag filled with 5 blue and 6 red marbles. A marble is taken at random from the bag, the colour is noted and then it i
il63 [147K]

Answer: 36/121

Step-by-step explanation:

There are 6 red marbles out of total 11.

The probability of drswing two red marbles is 6/11 x 6x11 = 36/121

4 0
3 years ago
KOUKLADINA HERE IS THE LIST OF BOTS>... I ALSO PUT THEM IN A MESSAGE TO YOU>>>>>>>>>>>>&g
Elodia [21]

Answer:

HUH WHAT DOES THIS MEAN?

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
Other questions:
  • Simplify<br>1. 7x + 11x<br>2. 3x-2y+4z-2x-3y+5z+6x+2y-3x<br><br>​
    5·2 answers
  • Given that BCA = 15° and mangle DCE = 38°, find ACE.
    5·1 answer
  • The speed of 10 Ferris wheels is sampled. The speed, measured in miles per hour, are
    6·1 answer
  • How do i solve 6x=5x+7 by using solving systems by elimination?
    8·2 answers
  • Two variables are correlated with r=−0.925. Which description best describes the strength and direction of the association betwe
    12·2 answers
  • Solve for x. 4 - (2x + 4) = 5
    10·2 answers
  • Someone help please<br><br> Find the sine of
    6·1 answer
  • Can y’all help me I’ll give the brain thingy
    14·1 answer
  • What is your favorite anime of all time? Mine's is One Piece and it is a really goated.
    13·2 answers
  • Helppp meeeeee please ​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!