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Pavlova-9 [17]
3 years ago
10

Given :f(x) =1/x+5 and g(x) =x-2 What are the restrictions of the domain of f(g(x))?

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
8 0

Answer:x≠-3

Step-by-step explanation:

emmainna [20.7K]3 years ago
5 0
I don't know if it's (1/x )+ 5 or 1/(x+5) anyways
g(x) = x-2 so in f(g(x)) you replace every x with x-2
f(g(x)) = (1/(x-2)) + 5 or 1/(x-2-5) = 1/(x-7)
if the function is like the first form so you avoid numbers which will make your denominator equals zero
x-2 = 0, x=2 or x-7 = 0, x=7
so if it's like first one answer is R - 2
if it's second answer is R - 7
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3 0
3 years ago
5. A life insurance policy costs $16.00 for every $1,000.00 of insurance. At
attashe74 [19]

Answer:

800.00

Step-by-step explanation:

so you give me a hint that was for every 16.00 it was 1000.00

i did 16x50=800

i got 50 from <u>50</u> in 50000 and the 16 from <u>16.00 so then i times 16 from 50 which is 800</u>

5 0
3 years ago
Pls help me understand this topic and help me answer the questions. I will mark the one most best explained branliest answer pls
MatroZZZ [7]

Answer:

Answer of given question are

i.9

ii.2

iii.3

8 0
3 years ago
Read 2 more answers
If <img src="https://tex.z-dn.net/?f=tan%20%28x%29%20%3D%20%5Cfrac%7B5%7D%7B12%7D" id="TexFormula1" title="tan (x) = \frac{5}{12
Alekssandra [29.7K]

Explanation:

First, we need to find the values of the sine and cosine of x knowing the value of tan x and x being in the 3rd quadrant. Since tan x = 5/12, using Pythagorean theorem, we know that

\sin x = -\frac{5}{13}\;\;\text{and}\;\;\cos x = -\frac{12}{13}

Note that both sine and cosine are negative because x is in the 3rd quadrant.

Recall the addition identities listed below:

\sin(\alpha + \beta) = \sin\alpha\sin\beta + \cos\alpha\cos\beta

\Rightarrow \sin(180+x) = \sin180\sin x + \cos180\cos x

\;\;\;\;\;\;= -\sin x = \dfrac{5}{13}

\cos(\alpha - \beta) = \cos\alpha \cos\beta + \sin\alpha \sin\beta

\Rightarrow \cos(180 - x) = \cos180\cos x + \sin180\sin x

\;\;\;\;\;\;=-\cos x = \dfrac{12}{13}

\tan(\alpha - \beta) = \dfrac{\tan\alpha - \tan\beta}{1 + \tan\alpha\tan\beta}

\Rightarrow \tan(360 - x) = \dfrac{\tan 360 - \tan x}{1 + \tan 360 \tan x}

\;\;\;\;\;\;= -\tan x = -\dfrac{5}{12}

Therefore, the expression reduces to

\sin(180+x) + \tan(360-x) + \frac{1}{\cos(180-x)}

\;\;\;\;\;= \left(\dfrac{5}{13}\right) + \left(\dfrac{5}{12}\right) + \dfrac{1}{\left(\frac{12}{13}\right)}

\;\;\;\;\;= \dfrac{49}{26}

5 0
2 years ago
What is the square root of 1.5
Natali5045456 [20]

Answer:

The answer is would be 1.2 or 1.22

8 0
3 years ago
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