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Pavlova-9 [17]
3 years ago
10

Given :f(x) =1/x+5 and g(x) =x-2 What are the restrictions of the domain of f(g(x))?

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
8 0

Answer:x≠-3

Step-by-step explanation:

emmainna [20.7K]3 years ago
5 0
I don't know if it's (1/x )+ 5 or 1/(x+5) anyways
g(x) = x-2 so in f(g(x)) you replace every x with x-2
f(g(x)) = (1/(x-2)) + 5 or 1/(x-2-5) = 1/(x-7)
if the function is like the first form so you avoid numbers which will make your denominator equals zero
x-2 = 0, x=2 or x-7 = 0, x=7
so if it's like first one answer is R - 2
if it's second answer is R - 7
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Peter has built a gazebo, whose shape is a regular heptagon, with a side length of $1$ unit. He has also built a pathway around
Sholpan [36]

Answer:

Area of pathway = 10.375 unit²

Step-by-step explanation:

Given - Peter has built a gazebo, whose shape is a regular heptagon, with

             a side length of 1 unit. He has also built a pathway around the

             gazebo, of constant width 1 unit, as shown below.

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5 0
3 years ago
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