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4 years ago

HELp PLEASE!!! RUNNING OUT OF TIME!!!!

Mathematics

2 answers:

ZanzabumX [31]4 years ago

5 0

I think that the answer is B

Tju [1.3M]4 years ago

5 0

F(x) = 6x + 2
f(x + 3) = 6(x + 3) + 2
f(x + 3) = 6x + 18 + 2
f(x + 3) = 6x + 20

The answer is
C.

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Slice for 5x+c=k for x

Degger [83]

Answer:

A - x = (k-c)/5

Step-by-step explanation:

To solve this problem, we would solve for x like we would in 2x = 6 :

5x + c = k

5x = k-c (subtract c from both sides)

x = k/5 - c/5 (divide 5 on both sides)

x = (k-c)/5 (simplify)

4 0

2 years ago

Read 2 more answers

The Wall Street Journal reports that 33% of taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deduction

Len [333]

Answer:

(a) n : 20 50 100 500

P (-200 < X - μ < 200) : 0.2886 0.4444 0.5954 0.9376

(b) The correct option is (b).

Step-by-step explanation:

Let the random variable X represent the amount of deductions for taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deductions on their federal income tax return.

The mean amount of deductions is, μ = $16,642 and standard deviation is, σ = $2,400.

Assuming that the random variable X follows a normal distribution.

(a)

Compute the probability that a sample of taxpayers from this income group who have itemized deductions will show a sample mean within $200 of the population mean as follows:

For a sample size of n = 20

$P(\mu-200$

$=P(-0.37$

For a sample size of n = 50

$P(\mu-200$

$=P(-0.59$

For a sample size of n = 100

$P(\mu-200$

$=P(-0.83$

For a sample size of n = 500

$P(\mu-200$

$=P(-1.86$

n : 20 50 100 500

P (-200 < X - μ < 200) : 0.2886 0.4444 0.5954 0.9376

(b)

The law of large numbers, in probability concept, states that as we increase the sample size, the mean of the sample ( $\bar x$ ) approaches the whole population mean ( $\mu_{x}$ ).