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scoundrel [369]
3 years ago
15

the sum of three numbers is 63. The first number is twice the second number, and the third number is three times the first numbe

r. Set these numbers​
Mathematics
1 answer:
HACTEHA [7]3 years ago
3 0

Answer:

Step-by-step explanation:

2x+x+3(2x)=63

3x+6x=63

9x=63

9x/9=63/9

X=7

2x=14

3(2x)=42

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A.) 10<br> B.) 25<br> C.) 20<br> D.) 15
Sergio [31]
2x+4=10
2x=6
x=3
2(3)+4= 10
(plus, on parallelograms like that, parallel sides are equal to each other)
7 0
3 years ago
What is the point of intersection when the system of equations below is graphed on the coordinate plane?
lora16 [44]

Answer:

<h2>not exist</h2>

Step-by-step explanation:

The coordinates of the intersection of the line are the solution of the system of equations.

\underline{+\left\{\begin{array}{ccc}x-y=1\\y-x=1\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad0=2\qquad\bold{FALSE}

The system of equations has no solution. Therefore, the lines are parallel (the intersection does not exist).

5 0
3 years ago
What are the critical values for a two-tailed test with a 0.01 level of significance when n is large and the population standard
Sunny_sXe [5.5K]
For a two-tailed test we need to halve 0.01, giving 0.005. Then we need to sutract 0.005 from 0.5, giving 0.5 - 0.005 = 0.495. Looking up the p value of 0.495 in an inverse normal probability table we obtain the value z = 2.5758. Therefore the critical values are -2.5758 and 2.5758.
4 0
3 years ago
Does 2/7 =11/37 because idk
Bad White [126]

Answer:

no. i do not think so.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
2x^2+9x+6=0 quadtratic equation
Studentka2010 [4]

Hello from MrBillDoesMath!

Answer:

x = ( -9 + sqrt(33) ) /4

and

x = ( -9 - sqrt(33) ) /4

Discussion:

Using the quadratic formula with a = 2, b = 9 and c = 6 gives

x = ( -b +\- sqrt(b^2-4ac) )/2a

x = ( -9 +\- sqrt(9^2 - 4*2*6)) / (2*2)   =>

x = ( -9 +\- sqrt (81- 48)) / 4                 =>

x = ( -9 +\- sqrt(33) ) /4

Thank you,

MrB

5 0
3 years ago
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