What is the interquartile range of the sequence 5,5,8,8,13,14,16,16,19,22,23,27,31 ?
Romashka-Z-Leto [24]
Answer:
The Interquartile range is 10.
Step-by-step explanation:
First, we will need to find the mean, the mean of this sequence is 16, you will now need to find quartile 1 and quartile 3. Quartile 1 is 13, and quartile 3 is 23. Lastly, subtract Quartile 3 and Quartile 1 will be the answer.
So, 23-13=10
The Answer will be 10, the interquartile range is 10.
Hope this helps!
There exist an abbreviation that ALL - S - T - C where all trigonometric functions in first quandrant are positive. S, T, and C are the first letters of the trigonometric functions that are positive in quadrant 2, 3, and 4, respectively. This also means that in the same quadrant, their reciprocals are also positive. For the given above, it is in Quadrant 3 where T is positive and cosine is negative.
Answer:
151°
Step-by-step explanation:
126°+221°+95°+57°+70+x=720° ( sum of interior angles of hexagon)
x + 569° =720°
x = 720°- 569°
=151°
Answer:
115.3 hertz
Step-by-step explanation:
For either interval, the value of the sample mean is given by the average of the lower and upper bound of the confidence interval. Since both intervals were constructed by using the same sample, both values should be equal.
For the first interval:
For the second interval:
1. The area of one face of the bar is
.. face area = (50 mm)*(90 mm) = 4500 mm^2
The area of two sides of the bar is
.. side area = (50 mm +90 mm)*(3.5 mm) = 490 mm^2
Together, those areas cover half the bar, so the total paper required is
.. 2*(4500 mm^2 +490 mm^2) = 9980 mm^2 . . . . . . 3rd selection
2. The length of the central rectangle is
.. 8 ft + 6 ft + 10 ft = 24 ft
Its width is 7 ft, so its area is
.. Arect = (7 ft)*(24 ft) = 168 ft^2
Each of the two triangles has a base of 8 ft and a height of 6 ft, so together, they have an area of
.. Atriangles = (8 ft)*(6 ft) = 48 ft^2
Then the total area of the prism is
.. Atotal = Arect +Atriangles
.. = (168 ft^2) +(48 ft^2)
.. = 216 ft^2
