1. A=15 and P=16
2. A=16 and P=20
3. A=12 and P=15
4 A=25 and P=20
5. A=28 and P=22
6. A=9 and P=20
7. A=14 and P=18
8. A=24 and P=20
9. A=30 and P=22
10. A=21 and P=20
Answer: 4188.8
Step-by-step explanation:
Known :
h = 10
d = 3
Asked :
V = ...?
Answer :
V = ¼πd²h
= ¼ × 3.14 × 3² × 10
= ¼ × 3.14 × 9 × 10
= <u>7</u><u>0</u><u>.</u><u>6</u><u>5</u>
<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>
Answer:
15: Yes, no, yes, yes, no; 16A: C = ($0.29)X + ($1.45)Y + ($2.50)Z; 16B: Yes
Step-by-step explanation:
For question 15: We need to multiply the widths and lengths given to see if they equal the area we are trying to achieve. Therefore, some of them work, and some do not.
For question 16:
Part A: We'll set a variable for the number of each supply she can buy. Pencils will be represented by X, pens by Y and Notebooks by Z, and we'll represent total cost by C. The total cost will therefore be represented by C = ($0.29)X + ($1.45)Y + ($2.50)Z.
Part B: We'll plug the numbers of items she wants to buy into our formula and see if it comes out to less than $20. So in this case C = ($0.29)(3) + ($1.45)(4) + ($2.50)(2). Therefore, C = $11.67, which is less than $20, so she can afford her school supplies.
Answer:
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