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2 years ago

PLZ HELP!!!!! BEST ANSWER WILL BE CHOSEN FOR BRAINLIEST!

Mathematics

1 answer:

sveticcg [70]2 years ago

3 0

Answer:

The angle measures of quadrilateral P'R'S'T are equal to the corresponding angle measures of quadrilateral PRST

Step-by-step explanation:

The transformation rule (x,y) ----> (x + 4 , y + 9 ) is an example of translation.

Translation is moving the points around.

During a translation the only thing that changes is the location of the points.

Everything else stays the same therefore the corresponding angles will be congruent.

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Tim is a wildlife biologist studying deer parasites

Leto [7]

During a study, he finds that 12 out of 32 deer were affected by parasites. How many of the 1200 deer in the local population would he expect to be affected by parasites?

Answer:

450

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2 years ago

30 POINTS FOR SOMEONE WHO ANSWERS MY QUESTIONS PLS IM FAILING

ziro4ka [17]

Answer:

ok i will answer only two which two do you want me to answer

Step-by-step explanation:

7 0

1 year ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

2 years ago

How many times longer is one centimeter than one millimeter

Nastasia [14]

A kilogram is 1,000 times larger than one gram (so 1 kilogram = 1,000 grams). A centimeter is 100 times smaller than one meter (so 1 meter = 100 centimeters). A dekaliter is 10 times larger than one liter (so 1 dekaliter = 10 liters).

3 0

2 years ago

I would like to know how to do these problems

miv72 [106K]

Hm. good question! multiply 5x2 i believe, which should be 10. Hope I helped!

4 0

2 years ago