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Doss [256]
3 years ago
7

84, 99, 88, 82, 95, 85

Mathematics
2 answers:
salantis [7]3 years ago
8 0
(84+99+88+82+95+84+98)/7 = 90 , so 98, or D. 
Ipatiy [6.2K]3 years ago
4 0

Answer:

Option: d is the correct answer.

               d. 98

Step-by-step explanation:

The scores of Myra's test are as follows:

               84, 99, 88, 82, 95, 85

Let 'x' be the minimum  score that is obtained by Myra in the last test so that the average is greater than 90 marks.

i.e.

\dfrac{84+99+88+82+95+85+x}{7}>90\\\\\\i.e.\\\\\\\dfrac{533+x}{7}>90\\\\\\i.e.\\\\\\533+x=90\times 7\\\\\\533+x>630\\\\\\x>630-533\\\\\\x>97

Hence, the minimum score has to be 98.

(   Since, the scores are in whole number )

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