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Yanka [14]
3 years ago
10

A line has a slope of 2 and passes through the point (1, 3). An equation of the line is

Mathematics
1 answer:
madam [21]3 years ago
8 0

Answer:

y = 2x + 1

Step-by-step explanation:

When given a point and a slope, use point-slope form of a line.

y - y₁ = m (x - x₁)

Here, (x₁, y₁) is (1, 3), and m = 2.

y - 3 = 2 (x - 1)

We can convert to slope-intercept form by solving for y:

y - 3 = 2x - 2

y = 2x + 1

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Dovator [93]

q + 12 - 2(q - 22) > 0     |use distributive property

q + 12 +(-2)(q) + (-2)(-22) > 0

q + 12 - 2q + 44 > 0      |combine like terms

(q - 2q) + (12 + 44) > 0

-q + 56 > 0       |subtract 56 from both sdies

-q > -56      |change the signs

<h3>q < 56</h3>

7 0
3 years ago
Read 2 more answers
Please see attached image and help with these absolute value problems - thank you
Novay_Z [31]

Answer:

{-infinity, infinity}

no solution

Step-by-step explanation:

|x| +15≥4

Subtract 15 from each side

|x| +15-15≥4-15

|x| ≥-11

This is always true so x can be and real number

{-infinity, infinity}

-2|5x+3| = 8

Divide by -2

-2/-2|5x+3| = 8/-2

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This can never happen because absolute values are zero or greater

no solution

6 0
3 years ago
how many different combinations are possible if four itemsare drawn from a group of seven different items
laiz [17]
You would just do 4 x 7, which means there are 28 combinations.
7 0
4 years ago
Pleasee help x.x 1. Solve the system by elimination-
patriot [66]
Q1. The answer is x = 1, y = 1, z = 0

<span>(i) -2x+2y+3z=0
</span><span>(ii) -2x-y+z=-3 
</span>(iii) <span>2x+3y+3z=5
</span><span>_________
Sum up the first and the third equation:
</span>(i) -2x+2y+3z=0
(iii) 2x+3y+3z=5
_________
5y + 6z = 5

Sum up the second and the third equation:
(ii) -2x-y+z=-3 
(iii) 2x+3y+3z=5
_________
2y + 4z = 2


(iv) 5y + 6z = 5
(v) 2y + 4z = 2
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Divide the fifth equation by 2
(iv) 5y + 6z = 5
(v) y + 2z = 1
________
Multiple the second equation by -3 and sum the equation
(iv) 5y + 6z = 5
(v) -3y - 6z = -3
________
2y = 2
y = 2/2 = 1


y + 2z = 1
1 + 2z = 1
2z = 1 - 1
2z = 0
z = 0


-2x-y+z=-3
-2x - 1 + 0 = -3
-2x = -3 + 1
-2x = -2
x = -2/-2 = 1



Q2. The answer is x = -37, y = -84, z = -35

<span>(i) x-y-z=-8 
(ii) -4x+4y+5z=7 
(iii) 2x+2z=4
______
</span>Divide the third equation by 2 and rewrite z in the term of x:
(iii) x+z=2
z = 2 - x
______
Substitute z from the third equation and express y in the term of x:
<span>x-y-(2-x)=-8 
x - y - 2 + x = 8
2x - y = 10
y = 2x - 10
______
Substitute z from the third equation and y from the first equation into the second equation:
</span><span>-4x + 4y + 5z = 7 
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-4x + 8x - 40 + 10 - 5x = 7
-x -30 = 7
-x = 30 + 7
x = -37
y = 2x - 10 = 2*(-37) - 10 = -74 - 10 = -84
z = 2 - x = 2 - 37 = -35</span>
8 0
4 years ago
EVERYONE, PLEASE HELP I NEED THIS DONE
zimovet [89]

Answer:

\frac{4}{5}

Step-by-step explanation:

\frac{32}{40}

Both 32 and 40 are divisible by 8.
32÷8=4

40÷8=5

Thus, the simplest form is \frac{4}{5}

7 0
2 years ago
Read 2 more answers
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