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Yanka [14]
3 years ago
10

A line has a slope of 2 and passes through the point (1, 3). An equation of the line is

Mathematics
1 answer:
madam [21]3 years ago
8 0

Answer:

y = 2x + 1

Step-by-step explanation:

When given a point and a slope, use point-slope form of a line.

y - y₁ = m (x - x₁)

Here, (x₁, y₁) is (1, 3), and m = 2.

y - 3 = 2 (x - 1)

We can convert to slope-intercept form by solving for y:

y - 3 = 2x - 2

y = 2x + 1

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Find the circumference of a circular field with a diameter of 16 yards.<br> (Let it = 3.14)
Tatiana [17]

Answer:

Hey there!

The circumference of a circle is \pi(d), where d is the diameter, and \\\pi is a constant roughly equal to 3.14.

The diameter is 16, so plugging this into the equation, we get 3.14(16)=50.24.

The circumference of the circle is 50.24 yards.

Hope this helps :)

3 0
3 years ago
X/x-3 times x-1/3-x​
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X-X^2/ (x-3)^2 try that I’m not 100% sure tho

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Two number are in the ratio 5:6 and their sum is 44 .Use z as variable
Mariulka [41]

Answer:

the numbers are 20 and 24

Step-by-step explanation:

The numbers are in the ratio 5 : 6 = 5z : 6z , where z is a multiplier

The numbers sum to 44, thus

5z + 6z = 44

11z = 44 ( divide both sides by 11 )

z = 4

Hence

5z = 5 × 4 = 20

6z = 6 × 4 = 24

The two numbers are 20 and 24

8 0
3 years ago
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Social media influence communication​
Alex

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3 years ago
On any given day, the probability that a large local river is polluted by carbon tetrachloride is 0.12. Each day, a test is cond
babymother [125]

Answer:

a) 0.2416

b) 0.4172

c) 0.0253

Step-by-step explanation:

Since the result of the test should be independent of the time , then the that the test number of times that test proves correct is independent of the days the river is correct .

denoting event a A=the test proves correct and B=the river is polluted

a) the test indicates pollution when

- the river is polluted and the test is correct

- the river is not polluted and the test fails

then

P(test indicates pollution)= P(A)*P(B)+ (1-P(A))*(1-P(B)) = 0.12*0.84+0.88*0.16 = 0.2416

b) according to Bayes

P(A∩B)= P(A/B)*P(B) → P(A/B)=P(A∩B)/P(B)

then

P(pollution exists/test indicates pollution)=P(A∩B)/P(B) = 0.84*0.12 / 0.2416 = 0.4172

c) since

P(test indicates no pollution)= P(A)*(1-P(B))+ (1-P(A))*P(B) = 0.84*0.88+  0.16*0.12 = 0.7584

the rate of false positives is

P(river is polluted/test indicates no pollution) = 0.12*0.16 / 0.7584 = 0.0253

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3 years ago
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